Answer: The number of moles of 
produced are, 0.287 moles.
Explanation : Given,
Mass of 
= 14.9 g
Molar mass of = 32 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 13 mole of react to give 8 moles of
So, 0.466 mole of react to give 
mole of
Therefore, the number of moles of produced are, 0.287 moles.
Answer:
In redox reactions, electrons are transferred from one species to another. If the reaction is spontaneous, energy is released, which can then be used to do useful work. To harness this energy, the reaction must be split into two separate half reactions: the oxidation and reduction reactions.
Answer:
0.2042 M is the original concentration of 
(aq) in the titrating solution.
Explanation:
Mass of 
= 0.217 g
Moles of 
1 mole of have 2 mole of As and 1 mole of 
have 1 mole of As.
So, from 1 mole of we will have 2 moles of
Then from 0.001096 mol of :
of
According to reaction, 1 mole of reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of
of cerium (IV) ions.
Volume of the acidic cerium{IV) sulfate = 21.47 ml =0.02147 L
1 mL = 0.001 L
![[Ce^{4+}]=\frac{0.004384 mol}{0.02147 L}=0.2042 M](https://tex.z-dn.net/?f=%5BCe%5E%7B4%2B%7D%5D%3D%5Cfrac%7B0.004384%20mol%7D%7B0.02147%20L%7D%3D0.2042%20M)
0.2042 M is the original concentration of (aq) in the titrating solution.
Answer:
¹/3 C3H8(g) + ⁵/3 O2(g)
Explanation:
The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;
C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;
For every 1 mole of C₃H₈(g) and 5 moles of O₂(g) produces 3 moles of CO₂(g) and 4 moles of H₂O(l).
Therefore to produce 1.00 mole of CO₂(g);
We represent it in ratio;
C₃H₈(g) : CO₂(g)
1 : 3
For more on evaluating moles in chemical reactions check out;
brainly.com/question/13967925
brainly.com/question/13969737
Answer:
Moles = 10.625 mol
Explanation:
Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,
Molarity = Moles / Volume of Solution ----- (1)
We can also rearrange this equation in terms of moles as,
Moles = Molarity × Volume of Solution ------(2)
Data Given;
Molarity = 4.25 mol.L⁻¹
Volume = 2.50 L
Now, putting value of Molarity and Volume in eq. 2,
Moles = 4.25 mol.L⁻¹ × 2.50 L
Moles = 10.625 mol
