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jolli1 [7]
2 years ago
9

List a couple general characteristics of primary consumers and list a few examples.

Chemistry
2 answers:
kakasveta [241]2 years ago
4 0
Primary consumers operate one level up from plants and eat only plants

small crustaceans as primary consumers

antelopes as primary consumers

mice are the primary consumers
SVEN [57.7K]2 years ago
4 0

Answer:

Primary consumers operate one level up from plants and eat only plants

small crustaceans as primary consumers

antelopes as primary consumers

mice are the primary consumers

Explanation:

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Describe the relationships among energy absorption, heat energy, and temperature.
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they are all an energy particle
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A mixture is made of two or more materials that A. cannot be separated by any means. B. cannot be separated by physical means. C
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The answer would be option D. can only be seperated by chemical means

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The songs of birds are part of a ritual to attractpotential partners of their own species. The song presents specific patterns r
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Explanation:

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3 years ago
The four fundamental forces are arranged in the increasing order of their relative strength.
natali 33 [55]

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The correct answer is - both act only between non-atomic particles.

Explanation:

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so, A would be here = gravity

B would be  = weak force

C  would be = strong force

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3 0
3 years ago
1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change
Inga [223]

Answer:

1 ) Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

Δs = positive

there is transition from solid to liquid and the melting point of mercury ( the point at which reaction will take place ) = 500⁰C

hence ΔSdecomposition = S⁻ Hg  -  S⁻ HgO =

Δh of reaction = 181.6 KJ

Temp = 500 + 273 = 773 k

hence ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

8 0
2 years ago
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