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docker41 [41]
3 years ago
6

Give an example of a rule of the natural world that a scientist can assume is always true.

Chemistry
1 answer:
vaieri [72.5K]3 years ago
4 0

Answer:

Laws of Nature are to be distinguished both from Scientific Laws and from Natural Laws. On the other account, the Necessitarian Theory, Laws of Nature are the principles which govern the natural phenomena of the world. That is, the natural world “obeys” the Laws of Nature.

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How much heat will be absorbed by 395g of water when it's temperature is raised by 55°C​
Firdavs [7]

Answer:

\boxed{\text{91 kJ}}

Explanation:

The formula for the heat released is

q = mCΔT

Data:

 m = 395 g

 C = 4.184 J·°C⁻¹g⁻¹

ΔT = 55 °C

Calculations:

q = 395 × 4.184 × 55 = 91 000 J = 91 kJ

The water will absorb \boxed{\textbf{91 kJ}} of energy.

3 0
3 years ago
Which equation represents a redox reaction?
labwork [276]

Answer:

D. 2NaBr + Cl_2\rightarrow 2NaCl + Br_2

Explanation:

Hello!

In this case, for the given set of chemical reactions, it is possible to infer that D. is a categorized as redox due to the following:

Since both chlorine and bromine remain as diatomic gases, their oxidation states in such a form is 0, but as anions with lithium cations they have a charge of - according to the following reaction and half-reactions:

2NaBr + Cl_2\rightarrow 2NaCl + Br_2

Cl_2^0+2e^-\rightarrow 2Cl ^-\\\\2Br^- \rightarrow  Br_2^0+2e^-

Unlike the other reactions whereas no change in the oxidation states is evidenced.

6 0
3 years ago
Read 2 more answers
A sample of calcium phosphate was found to have a mass of 125.3 g. How many molecules were contained in the sample?
Viktor [21]

The answer for the following problem is mentioned below.

  • <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules.</em></u>

Explanation:

Given:

mass of calcium phosphate (Ca_{3}(PO_{4} )_{2} ) = 125.3 grams

We know;

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = (40×3) + 3 (31 +(4×16))

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = 120 + 3(95)

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} )  = 120 +285 = 405 grams

<em>We also know;</em>

No of molecules at STP conditions(N_{A}) = 6.023 × 10^23 molecules

To solve:

no of molecules present in the sample(N)

We know;

\frac{m}{M} =\frac{N} }{}N÷N_{A}

\frac{405}{125.3} =\frac{N}{6.023*10^23}

N =(405×6.023 × 10^23) ÷ 125.3

N = 19.3 × 10^23 molecules

<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules</em></u>

3 0
3 years ago
Write the oxidation and reduction half reactions;
luda_lava [24]

Answer:

a)

Fe^{2+}⇒Fe^{3+}+e^-

Br_2+2e^-⇒2Br^-

b)

Mg⇒Mg^{2+}+2e^-

Cr^{3+}+e^-⇒Cr^{3+}

Explanation:

A)

Remember that positive number superscripts mean electrons lack and negative numbers mean electrons 'excess' (if we compare it with the neutral element). So, for the case of Fe2+ which is converted to Fe3+, we know that in Fe2+ there is a two electrons lack, while in Fe3+ there is a 3 electrons lack; it means that Fe2+ was converted to Fe3+ but releasing one electron:

Fe^{2+}⇒Fe^{3+}+e^-

The same analysis is applied to Br2; Br2 is a molecule which is said to have a zero superscript because it is an apolar covalent bond; and it is converted to Br-, which, according to what I wrote above, means that there is a one electron excess. So, Br2 must have received an electron in order to change to Br-; but Br2 can't change to Br- as simple as that because Br2 is a molecule, not an atom; it is a molecule that has two Br atoms, so, Br2 must give two Br- ions as products, but receiving one electron for each one:

Br_2+2e^-⇒2Br^-

b)

Applying the same, in Mg2+ there is a 2 electrons lack, and in Mg is not electron lack (its superscript is zero), so Mg must have released two electrons in order to change to Mg2+:

Mg⇒Mg^{2+}+2e^-

Cr3+ has a 3 electrons lack, and Cr2+ a two electrons one, so, Cr3+ must receive an electron to convert to Cr2+:

Cr^{3+}+e^-⇒Cr^{3+}

3 0
3 years ago
Read 2 more answers
All of the following are possible sources of error in a scientific investigation except for
Dimas [21]

Answer: Common sources of error include instrumental, environmental, procedural, and human. All of these errors can be either random or systematic depending on how they affect the results. Make sure you have your problem, hypothesis, evidence, analyze the data, ask yourself if the evidence supports ur hypothesis, draw conclusions, and communicate your results!

Explanation:

6 0
3 years ago
Read 2 more answers
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