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pogonyaev
2 years ago
15

Is HF the most polar among covalent bonds?

Chemistry
1 answer:
Sladkaya [172]2 years ago
3 0

Answer:

No.

Explanation:

HI is more polar than HF

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1.
Dahasolnce [82]

Answer:

22.5moles

Explanation:

using mole ratio,n(CO2)/n(o)=1/2

n(CO2)=1/2n(02)

n(CO2)=1/2×45

moles of carbon dioxide produced is 22.5moles

8 0
3 years ago
A tank of oxygen has a volume of 1650 L. The temperature of the gas inside is 35?C. If there are 9750 moles of oxygen in the tan
Paul [167]

Answer:

2192.64 PSI.

Explanation:

  • From the general law of ideal gases:

<em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the container in L (V = 1650 L).

n is the no. of moles of the gas in mol (n = 9750 mol).

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature of the gas in (T = 35°C + 273 = 308 K).

∴ P = nRT/V = (9750 mol)(0.082 L.atm/mol.K)(308 K)/(1650 L) = 149.2 atm.

  • <u><em>To convert from atm to PSI:</em></u>

1 atm = 14.696 PSI.

<em>∴ P = 149.2 atm x (14.696 PSI/1.0 atm) = 2192.64 PSI.</em>

4 0
3 years ago
How many grams of CaCl 2 are in .48 moles ?
Llana [10]

Answer:

We assume you are converting between moles CaCl2 and gram. You can view more details on each measurement unit: molecular weight of CaCl2 or grams This compound is also known as Calcium Chloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CaCl2, or 110.984 grams.

7 0
3 years ago
Read 2 more answers
What type of energy moves from warmer to cooler?
stich3 [128]

Answer:

Thermal energy is transferred from hot places to cold places by convection. Convection occurs when warmer areas of a liquid or gas rise to cooler areas in the liquid or gas.

Explanation:

8 0
3 years ago
A 365 L balloon is blown up inside at 283 K. It is then taken outside in the hot sun and Heated to 300K. What is the new volume?
asambeis [7]

V₁ = initial Volume of the balloon after it is blown up = 365 L

V₂ = new Volume of the balloon after it is taken outside = ?

T₁ = initial temperature of the balloon = 283 K

T₂ = new temperature of the balloon = 300 K

using the equation

V₁/V₂ = T₁/T₂

365/V₂ = 283/300

V₂ = 387 L

6 0
4 years ago
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