All categories

2 years ago

(17, -13), (17, 8) What is the slope through the line

Mathematics

2 answers:

Sophie [7]2 years ago

7 0

Answer:

undefined

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

= ( 8 - -13)/ ( 17-17)

= ( 8 +13)/ ( 17-17)

= 21/ 0

We can not divide by 0, so the slope is undefined

TEA [102]2 years ago

6 0

Answer:

Undefined slope:- the line is vertical

Step-by-step explanation:

The slope for the line joining the points (x1, y1) and (x2, y2)

= (y2-y1)/(x2-x1) so here it is:

(8 - (-13))/ (17-17)

= 21/0

As the denominator is zero the line is vertical.

You might be interested in

A savings account is started with an initial deposit of $500. The account earns 1.5% interest compounded annually.

Ghella [55]

A) A=500(1+0.015)^t
b)800=500(1.015)^t
800/500=1.015^t
t=log(800/500)/log(1.015)
t=31.6 years

3 0

2 years ago

The point(5/13,Y) IS IN THE 4TH quadrant corresponds to angle on the unit circle

shutvik [7]

4th quadrant is positive x (cos) and negative y (sin)

Use the Pythagorean Theorem to calculate the value of y (sin).
x² + y² = c²
5² + y² = 13²
25 + y² = 169
y² = 144
y = 12

Since the y-value is negative in the 4th quadrant, then y = -12

6 0

3 years ago

The town librarian bought a combination of new-release movies on DVD for $20 and classic movies on DVD for $8. Let

Artyom0805 [142]

Answer:

x = 16, y = 22: So C.

Step-by-step explanation:

3 0

2 years ago

Simplify<br><br> (2a²b)(4ab)

Anika [276]

Answer:

8a^3b^2

Step-by-step explanation:

4 0

2 years ago

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

3 years ago