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3 years ago

Anyone know how to do this???

Mathematics

1 answer:

QveST [7]3 years ago

8 0

Answer:

My guess would be B

Step-by-step explanation:

I have no definite way to solve this, so i may be wrong. Take this with a grain of salt. If this assignment is graded, I suggest wait for someone elses

answer on Brainly.

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American makes more than $80 a week in her boss wanted to give her a 12% raise how much money would making make a week after the

marshall27 [118]

80 x 12%= 9.60
80+ 9.60 = 89.60
Have a

8 0

3 years ago

Elyannie has no more than 90 Hershey Kisses. She puts the Hershey Kisses in 5 candy boxes.

Ira Lisetskai [31]

Answer:

So if she has no more than 90 Hershey's then she only has 90 Hershey's

She has 5 boxes

90/5 (divide)

=18

Step-by-step explanation:

Hope that Helped! :)

4 0

3 years ago

Read 2 more answers

What are three ways to get 15,638

laiz [17]

15,628+10, 15,000+638, 15,540+98.

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3 years ago

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In a recent poll, 370 people were asked if they liked dogs, and 7% said they did. Find the margin of error of this poll, at the

Dennis_Churaev [7]

Answer:

$ME=1.64\sqrt{\frac{0.07(1-0.07)}{370}}=0.0218$

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\hat p=0.07$ represent the estimated proportion for the sample

n=370 is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.10$ and $\alpha/2 =0.05$ . And the critical value would be given by: