<span>
<span>1st</span></span><span> formula 2n + 3m = 280
</span><span><span>
</span><span>2nd</span></span><span> formula 2n + 5m = 320
</span><span><span>
</span><span>rearrange 1st</span> formula to equal n:</span>
<span><span>2n = -3m + 280
</span>
</span><span>n = -3/2
m + 140
</span><span><span>
</span><span>rearrange 2nd</span> formula to equal n:</span>
<span><span>2n = -5m + 320
</span>
</span><span>n = -5/2m + 160
</span><span><span>
so now you have
</span>-3/2m + 140 = -5/2m + 160 </span>
<span><span>Rearrange to become:
</span>
</span><span><span>-3/2m + 5/2m = 160 - 140
</span>
</span><span>m = 20
</span><span>
</span>
<span>Now place 20 into the very 1st</span><span><span> equation in place
of the letter m
</span>
</span><span><span>2n + 3(20) = 280
</span>
</span><span><span>2n + 60 = 280
</span>
</span><span><span>2n = 220
</span>
</span><span>n = 110
</span><span><span>
</span>so it costs $110 per night, $20 per meal</span>
Answer:
-3q
Step-by-step explanation:
-q is actually -1q so you just divide 3 by -1 and get -3q
29 tables of relationships is the answer to your equation above … THANK ME LATER
2x²-3xy-2y²-2x-11y-12
Write -3xy as a difference
2x²+xy-4xy-2y²-2x-11y-12
write -2x as a difference
2x²+xy-4xy-2y²+4x-6x-11y-12
Write -11y as a difference
2x²+xy-4xy-2y²+4x-6x-8y-3y-12
Factor out 2x from the expression
2x×(x-2y-3)+xy-2y²+4x-8y-3y-12
Factor out y from the expression
2x×(x-2y-3)+y×(x-2y-3)+4x-8y-12
Factor out 4 from the expression
2x×(x-2y-3)+y×(x-2y-3)+4(x-2y-3)
Factor out x-2y-3 from the expression
Answer: (x-2y-3)x(2x+y+4)
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