1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Karo-lina-s [1.5K]
3 years ago
9

Find the permeter of a quadrilateral with vertices at C (2,4), D(1,1), E(5,0), and F(3,4). Round your answer to the nearest hund

redth when necessary.
Mathematics
1 answer:
denpristay [2]3 years ago
7 0

Answer:

12.76

Step-by-step explanation:

This is much easier to solve if you draw it out on a graph. The perimeter is the sum of all the sides. I used the Pythagorean theorem to find the hypotenuse.

{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\ c =  \sqrt{ {a}^{2} +  {b}^{2}  }

dc =  \sqrt{ {3}^{2}  +  {1}^{2} }  =  \sqrt{10}  \\  cf = 1 \\ fe =  \sqrt{ {4}^{2}  +  {2}^{2} }  =  \sqrt{20}  \\ de =  \sqrt{ {1}^{2} +  {4}^{2}  }  =  \sqrt{17}  \\  \sqrt{10}  + 1 +  \sqrt{20}  +  \sqrt{17}  = 12.76

You might be interested in
Mrs. McDonald's students have been working very hard during class, completing all class work and homework, and even attending tu
Natali5045456 [20]

Answer:

(13+83+85+87+90+91+93+97+98+99+100+100):12= 85,33

3 0
3 years ago
Find the product.<br> 0.18 × 4
ZanzabumX [31]
0.18 x 4 = 0.72
0.72 is the product
7 0
2 years ago
Find three consecutive numbers whose sum is 1020
krok68 [10]

what's up? the answer to this is 339+340+341

best of luck with your studies

6 0
2 years ago
Read 2 more answers
How can you check to see if a value of x is a zero of the polynomial
Mila [183]

Answer:

  substitute that value for x in the polynomial and see if it evaluates to zero

Step-by-step explanation:

A "zero" of a polynomial is a value of the polynomial's variable that make the expression become zero when it is evaluated. As an almost trivial example, consider the polynomial x-3. The value x = 3 is a zero because substituting that value for x makes the expression evaluate as zero.

  3 -3 = 0

___

Evaluating polynomials can be done different ways. Straight substitution for the variable is one way. Using synthetic division by x-a (where "a" is the value of interest) is another way. This latter method is completely equivalent to rewriting the polynomial to Horner form for evaluation.

__

In the attachment, Horner Form is shown at the bottom.

6 0
3 years ago
When the crispy treats have cooled Mrs. Williams cut theme into 30 equal pieces and she give 2/5 to her son and takes the rest t
stiv31 [10]

Answer: Mrs, William takes 18 treats to school.


Step-by-step explanation:

Given: When the crispy treats have cooled Mrs. Williams cut theme into 30 equal pieces .

She give 2/5 to her son, then the number of treats ahe give to her son = \frac{2}{5}30=12

Then, the number of treats Mrs. Williams take to school =30-12=18

Hence, Mrs, William takes 18 treats to school.

6 0
3 years ago
Other questions:
  • Combining like terms <br><br> simplify each expression<br> -v + 12v
    8·2 answers
  • Can you please help please please help me with this question i will give you a Brainiest
    7·1 answer
  • Solve the quadratic equation by completing the square.<br> =+x^2+16x +61=0
    14·1 answer
  • Leslie went out for a jog. When she returned she went to the tap and filled up her 500 mL reusable water bottle. She drank 250 m
    9·1 answer
  • The rational number halfway between 2/4 and 1/8
    9·2 answers
  • Find EF in the trapezoid.
    10·1 answer
  • 9u^2v and which term are like terms?
    14·1 answer
  • A jet travels 584 miles in 4 hours. At this rate how far could the jet fly in 13 hours?what is the rate of speed of the jet
    10·1 answer
  • Jennifer says that you can also write (12 — 3) X 2 for the phrase in the example. Is Jennifer correct?
    15·1 answer
  • It is known that y^24 − 256 = 0. Rewrite this equation in terms of x if x = y^4.​
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!