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3 years ago

Which expression is equivalent to 7/4?

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

5 0

An expression that is equal to 7/4 is:

6/4+1/4

Hope this helps :)

Flura [38]3 years ago

4 0

Answer:

6/4+1/4

Step-by-step explanation:

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If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

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3 years ago

Ella grew 3 over 4 of an inch last year. Ben grew 2 over 3 of an inch last year. How much more did Ella grow than Ben last year?

IrinaK [193]

Answer:

Ella grew $\frac{1}{12}$ of an inch more

Step-by-step explanation:

For this problem, you want to subtract Ben's growth from Ella's.

This expression would be $\frac{3}{4}$ - $\frac{2}{3}$ .

To work these out, they must have the same denominator (which should be the lowest common multiple or LCM).

In this case, the LCM is 12, so you want to multiply each side so the denominator is 12. This means the first fraction should be multiplied by $\frac{3}{3}$ and the second by $\frac{4}{4}$ .

This makes the expression $\frac{9}{12}$ - $\frac{8}{12}$ , which equals $\frac{1}{12}$ .

**This content involves adding and subtracting fractions, which you may want to revise. I'm always happy to help!

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