Suppose that m∠MKN = 55°. What is m∠MCN?
!please no absurd answers!
2 answers:
Taking into account that in the point of contact, the tangent to a circle is perpendicular to the radius, we have angles KMC = angle KNC = 90⁰.
In a 4-sides polygon (KMCN), the sum of all angles is 360⁰:
55+90+MCN+90=360
MCN=180-55=125⁰
Answer: MCN=125⁰
Answer:
angle M and N are right angles
we can draw a line joining M and N
so we’d have a triangle MNC AND KMN
both MNC AND KMN BECOME ISOSCELES TRIANGLES
so since we have 55 degrees for angle MKN. We have to find the other 2
180-55=125
now divide by 2 to get 62.5 for each of the remaining sides of triangle KMN
now to find the sides of triangle MNC
90-62.5= 27.5
27.5*2= 55
180-55=125=angle C
(sorry, it’s complex)
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