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const2013 [10]
3 years ago
7

Use the figure below to Find midsegment please help

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:

38 units.

Step-by-step explanation:

4x + 6 = \frac{1}{2}(4x + 44)      {midpoint theorem}

4x + 6 = \frac{1}{2}*4x +  \frac{1}{2}*44

4x + 6 = 2x + 22

4x -2x + 6 = 22

  2x   + 6  = 22

           2x = 22 -6

          2x = 16

            x = 16/2

            x = 8

Length of midsegment = 4x + 6 = 4*8 + 6

                                     = 32 + 6

                                     = 38

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Please help with 11,12,13
faltersainse [42]

Problem 11

<h3>Answer:  h = 2A/b</h3>

------------------

Explanation:

We need to get h by itself. To do so, we first multiply both sides by 2. Then we divide both sides by b

A = (1/2)*b*h

2A = b*h

b*h = 2A

h = 2A/b

================================================

Problem 12

<h3>Answers:</h3>
  • Equation:   (n+2)/5 = 14
  • Solution to that equation:  n = 68

------------------

Explanation:

The number n is increased by 2 to get n+2

Then we divide by 5 to get (n+2)/5

This is set equal to 14 to get the equation (n+2)/5 = 14

Solving the equation would look like this

(n+2)/5 = 14

n+2 = 5*14 .... multiply both sides by 5

n+2 = 70

n = 70-2 .... subtract 2 from both sides

n = 68

================================================

Problem 13

<h3>Answer: Not a solution</h3>

------------------

Explanation:

We'll replace every copy of x with -3 and simplify

-2x + 5 > 13

-2*(-3) + 5 > 13

6 + 5 > 13

11 > 13

The last inequality is false because 11 is not greater than 13. Since the last inequality is false, this makes the first inequality false when x = -3.

Therefore, x = -3 is not a solution.

3 0
3 years ago
Plz do this question if you did I will very appreciated you. plz.​
Nastasia [14]

The area formula of a circle is r^{2} × π.

With that being said, we can solve both problems!

Starting with part A:

-The radius we know is 21cm. From there, we can substitute in our formula with the new value.

21^{2} x π

From there, we can square our radius:

(21 x 21) x π

(441) x π

And finally, we can multiply by pi to get our answer.

(441) x π

1385.44236023

Which rounded to the nearest tenth is 1385.4. Therefore, the area of the porthole is 1385.4 centimetres.

The second part can be followed with the same process, hopefully you understand the concept enough to where you're comfortable solving problems like this on your own. Feel free to reach out if you have any further trouble!

<em>Hope this helped! :)</em>

5 0
3 years ago
What equation represents a line which is parallel to the y-axis
sasho [114]

Answer:

y-axis is x = 0

Step-by-step explanation:

if P(x, y) is any point on AB, then x = a. Hence, the equation of a straight line parallel to the y-axis at a distance from it is x = a. The equation of the y-axis is x = 0, since, the y-axis is parallel to itself at a distance 0 from it.

4 0
2 years ago
Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.
kolezko [41]

Answer:

A=4.5u^2

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3

y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9

The integral will be the subtraction of the curve y=3x and y=x^2  (In the graph you can see y=3x is the upper curve):

\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2

6 0
3 years ago
What's the rate and unit rate of 360 customers in 3
11111nata11111 [884]
Okay to start off the problem you make a fraction of 360/3. you then divide 360 by 3. 360÷3=120. so the rate and unit rate is 120 customers
3 0
3 years ago
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