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nordsb [41]
3 years ago
12

What is an algebraic expression for 58 less than a number n?

Mathematics
2 answers:
Korvikt [17]3 years ago
8 0

Answer:

n-58

Step-by-step explanation:

pashok25 [27]3 years ago
8 0

Answer: n - 58

Step-by-step explanation:

The n goes first. You are subtracting 58 to find the missing value once n is determined.

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A row of plaques cover 120 square
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Write an equation for the nth term of the arithmetic sequence -9,-4,1,6 then find a50
Dmitry_Shevchenko [17]

Answer :

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Hope it helped

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3 years ago
Read 2 more answers
A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.
vichka [17]

Answer:

14878.04878miles/hours^2

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

A=(Vf-Vi)/T where:

A=acceleration rate

Vf=final velocity

Vi=initial velocity

T=time required for passing from Vi to Vf.

Using the problem's data we have:

Vf=65miles/hour

Vi=6miles/hour

T=14.8seconds

Using the acceleration rate equation we have:

A=(65miles/hour - 6miles/hour)/14.8seconds, but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)

X=0.0041hours

Using X=0.0041hours in the previous equation instead of 14.8seconds we  have:

A=(65miles/hour - 6miles/hour)/0.0041hours

A=(61miles/hour)/0.0041hours

A=(61miles)/(hour*0.0041hours)

A=61miles/0.0041hours^2

A=14878.04878miles/hours^2

In conclusion, the acceleration rate is 14878.04878miles/hours^2

7 0
3 years ago
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