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nordsb [41]
2 years ago
12

What is an algebraic expression for 58 less than a number n?

Mathematics
2 answers:
Korvikt [17]2 years ago
8 0

Answer:

n-58

Step-by-step explanation:

pashok25 [27]2 years ago
8 0

Answer: n - 58

Step-by-step explanation:

The n goes first. You are subtracting 58 to find the missing value once n is determined.

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a carpenter can install 8 sheets of drywall in 10 minutes at this rate how long does it take to install one sheet of drywall how
Bezzdna [24]

I got A. 1.25 minutes; 1.25 hours. Hope that helps!

6 0
2 years ago
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Suppose it takes you 14 hour to drive to the movie theater at a rate of 40 mph. Your friend lives closer to the movie theater th
dezoksy [38]

Answer: (d)

Step-by-step explanation:

Given

It takes 14 hours with 40 mph to reach the theatre

so, the distance traveled is given by

\Rightarrow d_1=40\times 14\\\Rightarrow d_1=560\ \text{miles}

It is given that d is the distance from theatre to friend's house

So, d must be less than d_1 i.e.

d

So, the most appropriate option out of the given is option (d) as d must be less than 560 and it is possible that it maybe less than 160.

7 0
2 years ago
Question 8 (1 point)
creativ13 [48]
I believe x=3.
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4 0
2 years ago
What is the function for the arithmetic sequence 7,9,11,13,15,17
xeze [42]

Answer:


Step-by-step explanation: I would say y=x+2 or 2 because every number that you add 2 to, it gives you the solution which is the second number

Hope this helps!!!!

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5 0
2 years ago
Can you answer these please many thanks
givi [52]

Given: (a) 2(x+3)=2x+6 and (b) 4(y-3)=4y-12.

To find: The expanded form of the given expressions.

(c) 4(m+n)=4m+4n       (using a(b+c)=ab+ac)

(d) 3(5-q)=15-3q           (using a(b-c)=ab-ac)

(e) 5(2c+1)=10c+5          (using a(b+c)=ab+ac)

(f) 3(2x-5)=6x-15          (using a(b-c)=ab-ac)

(g) 7(4b-1)=28b-7          (using a(b-c)=ab-ac)

(h) 3(2x+y-5)=3((2x+y)-5)

⇒3(2x+y-5)=3(2x+y)-15         (using a(b-c)=ab-ac)

⇒3(2x+y-5)=6x+3y-15            (using a(b+c)=ab+ac)

(i) 2(6a-4b+3)=2((6a-4b)+3)

⇒2(6a-4b+3)=2(6a-4b)+6         (using a(b+c)=ab+ac)

⇒2(6a-4b+3)=12a-8b+6            (using a(b-c)=ab-ac)

(j)6(m+n+p)=6((m+n)+p)

⇒ 6(m+n+p)=6(m+n)+6p           (using a(b+c)=ab+ac)

⇒ 6(m+n+p)=6m+6n+6p            (using a(b+c)=ab+ac)

(k) y(y+2)=y^2+2y          (using a(b+c)=ab+ac)

(l) g(g-3)=g^2-3g           (using a(b-c)=ab-ac)

(m) n(4-n)=4n-n^2        (using a(b-c)=ab-ac)

(n) a(b+c)=ab+ac           (using a(b+c)=ab+ac)

(o) s(3s-4)=3s^2-4s        (using a(b-c)=ab-ac)

(p) 2x(x+5)=2x^2+10x     (using a(b+c)=ab+ac)

(q) 4y(x-3)=4xy-12y      (using a(b-c)=ab-ac)

(r) 5a(2b-5)=10ab-25a     (using a(b-c)=ab-ac)

(s) 4a(3b+2c)=12ab+8ac    (using a(b+c)=ab+ac)

(t) 5p(4p-5q)=20p^2-25pq    (using a(b-c)=ab-ac)

6 0
3 years ago
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