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2 years ago

PLEASE HELP THIS ASSIGNMENT IS OVER DUE

Mathematics

2 answers:

ruslelena [56]2 years ago

8 0

Answer:

Step-by-step explanation:

6x+3

Nutka1998 [239]2 years ago

4 0

simplified: 6x+3 (not sure if that’s what they’re asking but?)

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nataly862011 [7]

60 degrees. All angles add up to 180 degrees.

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A certain ball is dropped from a height of x feet. It always bounces up to 2/3 x feet. Suppose the ball is dropped from 10 feet

galina1969 [7]

Given that if a ball is dropped from x feet, it bounces up to 2/3 x feet.

And the ball is dropped from 10 feet, that is x=10 feet,

So,before the first bounce it travels 10 feet distance.

Between first and second bounce it travels $\frac{2}{3}* 10 + \frac{2}{3} * 10 = 20*(\frac{2}{3})$

Between second and third bounce, it travels $20*(\frac{2}{3})^{2}$

Between third and fourth bounce, it travels $20*(\frac{2}{3}) ^{3}$

Like that between 29th and 30th bounce, it travels $20*(\frac{2}{3} )^{29}$

Hence total distance traveled is

$10+20*(\frac{2}{3} )+20*(\frac{2}{3})^{2} + 20*(\frac{2}{3}) ^{3}+......+20*(\frac{2}{3})^{29}$

= $10+20[(\frac{2}{3}) +(\frac{2}{3}) ^{2} +(\frac{2}{3}) ^{3} +.....+(\frac{2}{3} )^{29} ]$

= $10+20[\frac{\frac{2}{3}*(1-(\frac{2}{3})^{29}) }{1-\frac{2}{3} }]$

= 10+20*2*(1- $(\frac{2}{3}) ^{29}$ )

= 49.9997 feet ≈ 50 feet approximately.

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Answer:

Option B is correct ...

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hope this helps..

Good luck on your assignment...

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