Adam works for an agency.

2 answers:

7 0

Hi there! I am here to help you with your question.

Adam normally earns 8.32 an hour. To get your answer, please follow my steps.

1. 8.32 * 6 (how much he has to work for).

Despite the two decimal places, we can ignore them and complete the process normally.

8 3 2
6
——————-
4 9 9 2

2. Add your decimals in the correct places aka 49.92!

3. Multiply 49.92 * 1/3 (a third) and you will get your answer: 16.64.

Hope this helped!

maksim [4K]3 years ago

5 0

The answer is he earns 8.32 an hour have a great day

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Hello please help me I don't get this at all

Stella [2.4K]

There are 1 rectangle and 2 triangles.
The area of the rectangle is 5 x 7 =35
The are of the triangle is 7 x 2 = 14(1/2) = 7
There are 2 triangles, so 7 x 2 = 14

14 + 35 = 49

49 is your answer

hope this helps

4 0

3 years ago

Read 2 more answers

At Sally's Hair Salon there are three hair stylists. 36% of the hair cuts are done by Chris, 26% are done by Karine, and the res

Marina86 [1]

Answer:

Probability that their hair was done by Amy is 0.475.

Step-by-step explanation:

We are given that Sally's Hair Salon there are three hair stylists. 36% of the hair cuts are done by Chris, 26% are done by Karine, and the rest are done by Amy.

Let the Probability of hair cutting done by Chris = P(C) = 0.36

Probability of hair cutting done by Karine = P(K) = 0.26

Probability of hair cutting done by Amy = P(A) = 0.368

Also, let NS = event that customer is not satisfied with his cutting

So, Probability that customers are not satisfied given that their hair cutting is done by Chris = P(NS/C) = 0.05

Probability that customers are not satisfied given that their hair cutting is done by Karine = P(NS/K) = 0.06

Probability that customers are not satisfied given that their hair cutting is done by Amy = P(NS/A) = 0.08

Now, a customer leaving the salon is selected at random. If the customer is not satisfied, the probability that their hair was done by Amy is given by = P(A/NS)

For finding the above probability we will use the concept of Bayes' Theorem;

SO, P(A/NS) = $\frac{\text{P(A) \times P(NS/A)}}{\text{P(C) \times P(NS/C) + P(K) \times P(NS/K) +P(A) \times P(NS/A) }}$ $\frac{P(A) \times P(NS/A) }{P(C) \times P(NS/C) +P(K) \times P(NS/K) +P(A) \times P(NS/A) }$