There are three fourths in six eights.
The equation is 1/2+3/x=3/4, it is still solvable
the equivalent of the equation is (1.x+2.3)/2.x = 3/4, or (x+ 6)/2.x=3/4, this last can be solved as follow: 4.(x+ 6) = 2x.3, 4x+ 24 = 6x, so 24=6x-4x=2x, and when 2x= 24 , it means x=24/2 =12, finally the equation is solvable because x=12 is a solution
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
I believe that it is A) 1/6. I think I learned how to do this but I don't remember.
Hope this helps. :)
