Answer:
25x = 75 (Because they are alternate interior angles)
=> x = 75/25
=> x = 3
So, x = 3
Because 25x is equal to 75, the two lines (u and v) are parallel
R=50 because 8×50=400 so that is what r would equal
The exponent would be 5 the fifth power, because since the number your using to multiply it by is 5 and you are multiplying is by 5 fives it would be 5 to the fifth power
Upper Tolerance
Remark
The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.
Solution
<u>Upper Limit</u>

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

Which results in

With a final result for the fractions of 45/64
So the upper tolerance = 3 45/64
<u>Lower Tolerance</u>
Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

Your answer should be 3 and 43/64
Answer:
b) in the fourth round, there was one team left in the tournament.
c) no because with only one team left, the tournament ends.
Answer:
right side
Step-by-step explanation: