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lora16 [44]
3 years ago
5

Please help me solve this?

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0

Answer:

  15x^4y^5z^2

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)(a^c) = a^(b+c)

3xy^4z^2\cdot 5x^2yx=(3\cdot 5)x^{1+2+1}y^{4+1}z^2=15x^4y^5z^2

_____

<em>Comment on the rule of exponents</em>

You can see where the rule comes from when you consider that an exponent signifies repeated multiplication.

x² = x·x . . . . . . the 2 signifies that x is a factor 2 times

x³ = x·x·x . . . . the 3 signifies that x is a factor 3 times

The product of these is ...

  (x²)(x³) = (x·x)(x·x·x) = x·x·x·x·x = x⁵ = x²⁺³

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Step-by-step explanation: Here we're given the function f(x) = -3x + 2 and we are asked to find f(2).

In other words, if we put an <em>x</em> into our function, we get a -3x + 2 out so what happens when we put a 2 into the function?

Well if we put a 2 into the function,

that's f(2) and we get -3(2) + 2 out.

Now all we have to do is simplify on the right side.

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What is the equation of a line perpendicularto y=-2/5x-1 that passes through(2,-8)​
Andrews [41]
<h2>Answer: y =  ⁵/₂ x - 13   OR  y + 8 =  ⁵/₂ x - 5 </h2>

<h3>Step-by-step explanation:</h3>

<u>Find the slope of the perpendicular line</u>

When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are <em>negative-reciprocal</em>s of each other.

⇒  if the slope of this line = - ²/₅

      then the slope of the perpendicular line (m) = ⁵/₂

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

                                ⇒  y - (-8) =  ⁵/₂ (x - 2)

                                   ∴  y + 8 = ⁵/₂ (x - 2)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

                  since   y + 8 =  ⁵/₂ (x - 2)

                                    y =  ⁵/₂ x - 13

7 0
2 years ago
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