(a) If
is the mass (in mg) remaining after
years, then
(b)
(c)
Answer:
Step-by-step explanation:
You need to complete the square.
C(x) = 0.02(x^2 - 1000x ...) + 11000
C(x) = 0.02 (x^2 - 1000x + 500^2) + 11000 - 5000
C(x) = 0.02 (x^2 - 1000x + 500^2) + 6000
C(x) = 0.02(x - 500)^2 + 6000
Now if you look at the answer you will find that the square is completed. That means that number of tractors you could produce is 500 at a cost of 6000
There is a flow to this question that you may have trouble understanding.
First of all the 500^2. That comes from taking 1/2 of 1000 and squaring it. That's what you need to complete the square.
Bur that is not what you have adding into the equation. Remember that there is a 0.02 in front of the brackets.
500^2 = 250000
0.02 * 250000 = 5000
So that number must be subtracted to make the square = 0. When you remove the brackets, you should get 11000 all in all.
So what you have outside the brackets is 11000 - 5000 = 6000
The rest is just standard for completing the square.
Answer:
(-1/3; 4)
Step-by-step explanation:
(-2, -1) , (-1, 6 ) and (2, 7).
x=(-2-1+2)/3= -1/3
y=(-1+6+7)/3=12/3=4
=> (-1/3; 4)
The answer is D
Hope this helps
(0,a)
it didnt move left or right on the x-axis
it went up a units (since its half of 2a)
