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Sveta_85 [38]
3 years ago
9

There are three choices of jellybeans: grape, cherry and orange. If the probability of getting a grape is 3/10 and the probabili

ty of getting cherry is 1/5, what is the probability of getting orange?
Mathematics
2 answers:
melisa1 [442]3 years ago
7 0

can u plzz explain me the question

nataly862011 [7]3 years ago
4 0

Answer:

5/10, or 1/2

Step-by-step explanation:

If the probability of getting a grape is 3/10, and the probability of a cherry is 1/5 or 2/10, then the probability of getting orange is 5/10.

3/10+2/10=5/10

10/10-5/10=5/10

Simplified: 1/2

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I the cafeteria there are 7 teachers 48 girls and 45 boys. What is the probability that a person chosen at random from the cafet
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Total people in the cafeteria = 7 + 48 + 45 = 100

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The probability would be the number of boys over the total number of people:

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An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

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