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Sveta_85 [38]
3 years ago
9

There are three choices of jellybeans: grape, cherry and orange. If the probability of getting a grape is 3/10 and the probabili

ty of getting cherry is 1/5, what is the probability of getting orange?
Mathematics
2 answers:
melisa1 [442]3 years ago
7 0

can u plzz explain me the question

nataly862011 [7]3 years ago
4 0

Answer:

5/10, or 1/2

Step-by-step explanation:

If the probability of getting a grape is 3/10, and the probability of a cherry is 1/5 or 2/10, then the probability of getting orange is 5/10.

3/10+2/10=5/10

10/10-5/10=5/10

Simplified: 1/2

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Make m the subject of the following equation:<br> x = 4k(n + m)
inna [77]

Step-by-step explanation:

x=4kn+4km

x-4kn=4km

divide both sides by 4k

m=x-n

8 0
2 years ago
Suppose R = {1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27} r d
Free_Kalibri [48]

The intersection of sets R and D is give by the following set:

R ∩ D = {3, 9, 15}.

<h3>What is the missing information?</h3>

This problem is incomplete, but researching it on a search engine, we find that it asks the intersection of sets R and D.

<h3>What is the set that is the intersection of two sets?</h3>

The set that is the intersection of two sets is composed by the elements that belong to both sets.

For this problem, the sets are given as follows:

  • R = {1,3,5,7,9,11,13,15,17}.
  • D={3,6,9,12,15,18,21,24,27}

Hence the intersection is given by:

R ∩ D = {3, 9, 15}.

As the elements 3, 9 and 15 are the only ones that belong to both sets.

More can be learned about intersection of sets at brainly.com/question/11439924

#SPJ1

3 0
1 year ago
On a piece of paper, graph f(x)=16x0.5^x. Then determine which answer choice matches the graph you drew.
Reil [10]

9514 1404 393

Answer:

  A

Step-by-step explanation:

You can use x=0 and x=1 to find points that must be on the graph.

  f(0) = 16·0.5^0 = 16

  f(1) = 16·0.5^1 = 8

Only graph A matches these points.

7 0
3 years ago
Please help with these questions!!!
klasskru [66]

Answer:

Step-by-step explanation:

Q1: (x-1) * (x+1) * (x-2) * (x+2)

Q2: x'1 = -1/3, x'2 =2

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2 years ago
Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,
alekssr [168]
Hey there :)

- tan²x + sec²x = 1    or    1 + tan²x = sec²x

sin²x + cos²x = 1 
Divide the whole by cos²x

\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}

\frac{sinx}{cosx} = tanx so \frac{sin^2x}{cos^2x} = tan^2x
and
\frac{1}{cosx} = secx so \frac{1}{cos^2x} = sec^2x

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

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3 0
3 years ago
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