The question is incomplete ; we could calculate the least number of cars he can still wash for the week expressed in inequality form.
Answer:
x > 13 ; 13
Step-by-step explanation:
Given that :
Anticipated work hour for entire week = 60.2 hours
Hours worked = 27.7 hours
Rate of car wash = 2.5 per hour
Hours left to work for the week :
60.2 - 27.7 = 32.5
Hours left / unit rate of car wash
32.5 / 2.5
= 13
Hours worked +( hours left * unit rate) > anticipated hours
27.7 + 2.5x < 60.2
2.5x > 60.2 - 27.7
2.5x > 32.5
x > 32.5 / 2.5
x > 13
Hence ; Sam could still wash over 13 cars this week
4 x 100,000 + 5 x 1,000 + 6 x 100 + 1 x 10 + 2 x 1
B)70 because sina=cos(90-a)
Answer:
20 weeks
Step-by-step explanation:
Im great in math!!
