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Vsevolod [243]
4 years ago
13

HELP ME DO THIS y=2x+4 -5x-5y=-5

Mathematics
2 answers:
meriva4 years ago
7 0
Y=2x+4
-5x-5y=-5
subsitute 2x+4 for y
-5x-5(2x+4)=-5
-5x-10x-20=-5
-15x-20=-5
add 20 to both sdies
-15x=15
divide by -15
x=-1

subsitute
y=2(-1)+4
y=-2+4
y=2


x=-1
y=2
Helen [10]4 years ago
3 0
\left \{ {{y=2x+4} \atop {-5x-5y=-5}} \right. \\\\ substitute\ first\ equation\ into \ the\ second\\\\
-5x-5(2x+4)=-5\\\\
-5x-10x-20=-5\\\\
-15x-20=-5\ \ \ | add\ 20\\\\
-15x=15\ \ \ | divide\ by\ -15\\\\
x=-1\\\\
y=2*(-1)+4=-2+4=2
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Use long division to determine the decimal equivalent of fraction with numerator 2 and denominator 3. 0 point 6 bar 0 point 7 ba
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Answer:

The correct answer is A

0.\bar6

Step-by-step explanation:

We want to determine the decimal equivalence of \frac{2}{3}.


We perform the long division as shown in the attachment.


Note that in carry out the long division, the denominator which is 3, will be outside the long division sign, while the numerator which is 2, will be inside the long division sign.

We see that the quotient of our long division is 0.6666....


We can rewrite this as 0.\bar6


Therefore \frac{2}{3}=0.\bar6.


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3 years ago
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Find the surface area of the prism (photo attached)
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- Find area of the bottom, top, left, right, back, and front of the prism.

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What is algebra in 5th grade
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What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
23/7y state restrictions
qwelly [4]

The restrictions on the variable of the given rational fraction is y ≠ 0.

<h3>The types of numbers.</h3>

In Mathematics, there are six (6) common types of numbers and these include the following:

  • <u>Natural (counting) numbers:</u> these include 1, 2, 3, 4, 5, 6, .....114, ....560.
  • <u>Whole numbers:</u> these comprises all natural numbers and 0.
  • <u>Integers:</u> these are whole numbers that may either be positive, negative, or zero such as ....-560, ...... -114, ..... -4, -3, -2, -1, 0, 1, 2, 3, 4, .....114, ....560.
  • <u>Irrational numbers:</u> these comprises non-terminating or non-repeating decimals.
  • <u>Real numbers:</u> these comprises both rational numbers and irrational numbers.
  • <u>Rational numbers:</u> these comprises fractions, integers, and terminating (repeating) decimals such as ....-560, ...... -114, ..... -4, -3, -2, -1, -1/2, 0, 1, 1/2, 2, 3, 4, .....114, ....560.

This ultimately implies that, a rational fraction simply comprises a real number and it can be defined as a quotient which consist of two integers x and y.

<h3>What are restrictions?</h3>

In Mathematics, restrictions can be defined as all the real numbers that are not part of the domain because they produces a value of 0 in the denominator of a rational fraction.

In order to determine the restrictions for this rational fraction, we would equate the denominator to 0 and then solve:

23/7y;

7y = 0

y = 0/7

y ≠ 0.

Read more on restrictions here: brainly.com/question/10957518

#SPJ1

Complete Question:

State any restrictions on the variables 23/7y

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