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Sliva [168]
3 years ago
9

Please help me I keep on getting the third box wrong

Mathematics
2 answers:
JulijaS [17]3 years ago
8 0

Maybe try 1 I cannot figure it out

PolarNik [594]3 years ago
6 0

Answer:

(2 {a}^{2}  + 1)(1 {a}^{2}  + 9)

Step-by-step explanation:

2 {a}^{4}  + 19 {a}^{2}  + 9 \\ 2 {a}^{4}  +  {a}^{2}  + 18{a}^{2}  + 9 \\ {a}^{2} (2 {a}^{2}  + 1) + 9(2 {a}^{2}  + 1) \\ (2 {a}^{2}  + 1)( {a}^{2}  + 9) \\

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Nana76 [90]

x − 3 = 6 − 2 x = − 8 √ x = 3

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3 years ago
Can someone please explain this to me step by step since I have a test next Monday and I don’t understand this problem that well
AfilCa [17]

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8 0
2 years ago
The length of a rectangle is 2 centimeters less than its width. What are the dimensions of the rectangle if its area is 195 squa
JulijaS [17]

Answer:

Length=15 cm

Width=13 cm

Step-by-step explanation:

-Let x be the width dimension, the length will be (x-2)

-The area of a rectangle is given by the formula;

A=lw

#We substitute the length and width values and equate to the given area:

A=lw\\195=x\times (x-2)\\\\195=x^2-2x

#Rewrite as a quadratic and solve for x:

195=x^2-2x\\\\x^2-2x-195=0\\\\\# Use \ the \ Quadratic\  formula \ to\  solve:\\\\x_1,x_2=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\therefore x_1,x_2=\frac{-(-2)\pm\sqrt{(-2)^2-4\times 1\times(-195)}}{2\times 1}\\\\\\x_1=15, x_2=-13

Since dimensions are always positve, the x value is 15

x=15

x=13

Hence, the dimensions of the rectangle are length=15 cm and width=13 cm

8 0
3 years ago
What is the distance???
maxonik [38]

Answer:

5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A blimp travels 255 feet in 1/2minute, 510 feet in 1/6 minute, and 3,060 feet in 1 minute.
borishaifa [10]

Answer:

We conclude that there is NOT a proportional relationship between the distance the blimp travels and the time it travels.

Step-by-step explanation:

We know if y varies directly with x, we get the equation

y ∝ x

y = kx

k = y/x

where k is called the constant of variation.

In our case we are given:

A blimp travels 255 feet in 1/2 minute

  • A blimp travels 255 feet in 1/2minute.

here:

y = 255, and x = 1/2 = 0.5

so substituting y = 255 and x = 0.5 in the equation

k = y/x

k = 255 / 0.5

k = 510

A blimp travels 510 feet in 1/6 minute

here:

y = 510 , and x = 1/6

so substituting y = 510 and x = 1/6 in the equation

k = y/x

k = [510] / [1/6]

k = 3060

A blimp travels 3,060 feet in 1 minute

here

y = 3,060, and x = 1

so substituting y = 3,060 and x = 1 in the equation

k = y/x

k = 3,060 / 1

k = 3060

<u>HERE IS THE VARIATION OF THE CONSTANT OF VARIATION:</u>

A blimp travels 255 feet in 1/2 minute

k = 510

A blimp travels 255 feet in 1/2 minute

k = 3060

A blimp travels 3,060 feet in 1 minute

k = 3060

It is clear that the constant of variation does not remain constant.

Therefore, we conclude that there is NOT a proportional relationship between the distance the blimp travels and the time it travels.

6 0
3 years ago
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