The speed of the current in a creek is 2mph. A person can kayak 10 mi upstream in the same time that it takes him to kayak 14 mi
1 answer:
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F you just want to see the really short way, just skip down to AAAAAAAAAAAA
so, here is the long explanation
exponential properties
don't forget pemdas
2x^2=2(x^2)
so
=
AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
remember
so we can seperate the constants
we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not
terfor the answer must have 2/3 in it
the only one that hsa that is A
ANSWER IS A
so, here is the long explanation
exponential properties
don't forget pemdas
2x^2=2(x^2)
so
AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
remember
so we can seperate the constants
we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not
terfor the answer must have 2/3 in it
the only one that hsa that is A
ANSWER IS A
Given:
The expressions are:
To find:
The value of given expression by using integer tiles.
Solution:
We have,
Here, both number are positive. When we add 6 and 3 positive integer tiles, we get 9 positive integer tiles as shown in the below figure. So,
Similarly,
Here, 6 is positive and -4 is negative. It means we have 6 positive integer tiles and 4 negative integer tiles.
When we cancel the positive and negative integer tiles, we get 2 positive integer tiles as shown in the below figure. So,
Here, 6 is positive and -6 is negative. It means we have 6 positive integer tiles and 6 negative integer tiles.
When we cancel the positive and negative integer tiles, we get 0 integer tiles as shown in the below figure. So,
Therefore, .
You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.
To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.
First question:
To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is
Second question:
To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is
Third question:
To get exactly one six, it can either be the first, second or third roll.
In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.
In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus
And since there are three of these combinations, The answer is
Fourth question:
Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is
