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3 years ago

10

Six staff members carved pumpkins for a school contest. The carved pumpkins were auctioned at the event and in total, they raise

d $180 for the school! The final bid on Dr. Tracy's pumpkin was $10 more than the final bid on Mr. Nelson's pumpkin. Mr. Nelson's, Mrs. Ennis', and Mr. Pizzica's pumpkins each earned the same amount. Ms. Scelfo's and Mr. Hartshorn's pumpkins each brought in the same amount of money as Dr. Tracy's. What were the final bids on the individual pumpkins carved by each of the six people?

1 answer:

atroni [7]3 years ago

6 0

Answer:

Dr. Tracy - $35

Ms. Scelfo - $35

Mr. Hartshorn - $35

Mr. Nelson - $25

Mrs. Ennis - $25

Mr. Pizzica - $25

Step-by-step explanation:

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Answer:

f

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3 years ago

The average income, I, in dollars, of a lawyer with an age of x years is modeled with the following function:

Alinara [238K]

The answer is 37 years old.

I = -425x² + 45500x -650000
I = 450000

-425x² + 45500x -650000 = 450000
-425x² + 45500x - 650000 - 450000 = 0
-425x² + 45500x - 1100000 = 0

Divide all factors by 25:
- 17x² + 1820x - 44000 = 0

This is quadratic equation (ax² + bx + c = 0)
$x_{1,2} = \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a} = \frac{-1820+/- \sqrt{ 1820^{2}-4*(-17)*(-44000) } }{2*(-17)} = \\ \\ = \frac{-1820+/- \sqrt{3312400-2992000 } }{-34} = \frac{-1820+/- \sqrt{320400} }{-34} =\frac{-1820+/- 566}{-34} \\ \\ 
x_1= \frac{-1820+ 566}{-34}= -37 \\ \\ 
x_2 = \frac{-1820- 566}{-34}=70$

Since, the youngest age is needed, the correct answer is x = 37

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3 years ago

Find all the missing values to make the equation true

Georgia [21]

The missing value in the logarithm are as follows:

log₃ 7 - log₃ 2 = log₃ (7 / 2)

log₉ 7 + log₉ 4 = log₉ 28
log₆ 1 / 81 =
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<h3>How to solve logarithm?</h3>

Using logarithm rule,

logₐ b - logₐ c = logₐ (b / c)

logₐ b + logₐ c = logₐ (b × c)

Therefore,

log₃ 7 - log₃ 2 = log₃ (7 / 2)

log₉ 7 + log₉ 4 = log₉ (7 × 4) = log₉ 28

log₆ 1 / 81 = log₆ 81⁻¹ = log₆ 3⁻⁴ = - 4 log₆ 3

learn more on logarithm here: brainly.com/question/24515212

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2 years ago

-(x + 2) - 2x = -2( x + 1)

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4 years ago

Read 2 more answers

Q 1 PLEASE HELP ME FIGURE THIS OUT 2

dimulka [17.4K]

Answer: $\frac{\pi }{3}$

<u>Step-by-step explanation:</u>

cot is $\frac{cos}{sin}$ on the Unit Circle. When is cos = $\frac{1}{2}$ and sin = $\frac{\sqrt{3}} {2}$ ? In other words, where is the coordinate $(\frac{1}{2},\frac{\sqrt{3}} {2})$ on the Unit Circle?

It occurs at 60° = $\frac{\pi }{3}$ radians

**************************************************************************************

Answer: cot θ

<u>Step-by-step explanation:</u>

sec (90 - θ) * cos θ

= $\frac{1}{cos (90 -\theta)}$ * cos θ

= $\frac{cos\theta}{cos(90 - \theta)}$

= $\frac{cos\theta}{cos90*cos\theta+sin90*sin\theta}$

= $\frac{cos\theta}{0*cos\theta+1*sin\theta}$

= $\frac{cos\theta}{sin\theta}$

= cot θ

**************************************************************************************

Answer: BC = √5, AC = 2√5

<u>Step-by-step explanation:</u>

$\frac{\pi} {3}$ = 60°, which means ΔABC is a 30°-60°-90° triangle so we can use the side length formulas: x - x√3 - 2x.

∠C is the 60°. It matches to side AB so: AB = x√3 = √15 ⇒ x = √5

∠A is the 30°. It matches to side BC so: BC = x = √5

∠B is the 90°. It matches to side AC so: AC = 2x = 2(√5) = 2√5

**************************************************************************************

Answer: k = 4, RS = 12, QS = 28

<u>Step-by-step explanation:</u>

$\frac{QR}{MN} = \frac{RS}{NO}= \frac{QS}{MO}$

$\frac{24}{6} = \frac{RS}{3}= \frac{QS}{7}$

proportionality constant k can be found with $\frac{QR}{MN}$ = $\frac{24}{6}$ = 4

$\frac{QR}{MN} = \frac{RS}{NO}$

→ 4 = $\frac{RS}{3}$

→ 4(3) = RS

→ 12 = RS

$\frac{QR}{MN} = \frac{QS}{MO}$

→ 4 = $\frac{QS}{7}$

→ 4(7) = QS

→ 28 = QS

3 0

4 years ago