Given:
Planes X and Y are perpendicular to each other
Points A, E, F, and G are points only in plane X
Points R and S are points in both planes X and Y
Lines EA and FG are parallel
The lines which could be perpendicular to RS are EA and FG.
Answer:
Center: (-3,-2)
Radius: √6
The graph is attached.
Step-by-step explanation:
The equation of the circle has the form:
![(x -h)^{2}+(y-k)^{2}=r^{2}](https://tex.z-dn.net/?f=%28x%20-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%3Dr%5E%7B2%7D)
Where (h,k) is the point of the center of the circle and r is the radius of the circle.
The equation given in the problem is
![(x +3)^{2}+(y+2)^{2}=6](https://tex.z-dn.net/?f=%28x%20%2B3%29%5E%7B2%7D%2B%28y%2B2%29%5E%7B2%7D%3D6)
Therefore:
h=-3
k=-2
The center is at (-3,-2)
And the radius is:
![r^2=6\\r=\sqrt{6}](https://tex.z-dn.net/?f=r%5E2%3D6%5C%5Cr%3D%5Csqrt%7B6%7D)
Then, you can graph it has you can see in the image attached.
Answer:
yor answer is 52
Step-by-step explanation: