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harkovskaia [24]
3 years ago
8

PLZ HELP ME OUT!!!! Solve for x. Round your answer to two decimal places. Show your work for full credit. Will give Brainliest.

Mathematics
1 answer:
masya89 [10]3 years ago
3 0

9514 1404 393

Answer:

  37.74

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. The one applicable here is ...

  Sin = Opposite/Hypotenuse

  sin(32°) = 20/x

  x = 20/sin(32°)

  x ≈ 37.74

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$90 is what percent of $100?<br><br> I need help.
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90%

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3 years ago
What is the answer to 93+(68+7)
Rasek [7]

93+(68+7)do whats in the parenthesis first

93(75)

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6975 is your answer plz rate my answer as brainliest


7 0
3 years ago
30 pts ! The height of the Ferris wheel in feet can be represented by the function 50 cos (π/15(x-10))+52 with time in x seconds
Dahasolnce [82]

h = 50 cos ( pie(x - 10 )/15 ) + 52

80 = 50 cos ( pie( x - 10 )/15 ) + 52

80 - 52 = 50 cos ( pie( x - 10 )/15 )

28 = 50 cos ( pie( x - 10 )/15 )

cos ( pie( x - 10 )/15 ) = 28/50

cos ( pie( x - 10 )/15 ) = 56/100

cos ( pie( x - 10 )/15 ) = cos ( 56 )

cos ( pie( x - 10 )/15 ) = cos ( 0.3111 pie )

Thus ;

pie( x - 10 )/15 = 0.3111 pie

( x - 10 )/15 = 0.3111

x - 10 = 15 × 0.3111

x - 10 = 4.6665

x = 10 + 4.6665

x = 14.6665 [ approximately ]

Thus the correct answer is exactly what u chose goodjob .....

7 0
3 years ago
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
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Katen [24]
The answer is 10 dollars
4 0
3 years ago
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