90%
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
93+(68+7)do whats in the parenthesis first
93(75)
multiply them together
6975 is your answer plz rate my answer as brainliest
h = 50 cos ( pie(x - 10 )/15 ) + 52
80 = 50 cos ( pie( x - 10 )/15 ) + 52
80 - 52 = 50 cos ( pie( x - 10 )/15 )
28 = 50 cos ( pie( x - 10 )/15 )
cos ( pie( x - 10 )/15 ) = 28/50
cos ( pie( x - 10 )/15 ) = 56/100
cos ( pie( x - 10 )/15 ) = cos ( 56 )
cos ( pie( x - 10 )/15 ) = cos ( 0.3111 pie )
Thus ;
pie( x - 10 )/15 = 0.3111 pie
( x - 10 )/15 = 0.3111
x - 10 = 15 × 0.3111
x - 10 = 4.6665
x = 10 + 4.6665
x = 14.6665 [ approximately ]
Thus the correct answer is exactly what u chose goodjob .....
Answer:
0.0082 = 0.82% probability that he will pass
Step-by-step explanation:
For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:
.
If the student makes knowledgeable guesses, what is the probability that he will pass?
He needs to guess at least 9 answers correctly. So









0.0082 = 0.82% probability that he will pass