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2 years ago

MATH HELP! BRAINLIESTT!!

Mathematics

2 answers:

shtirl [24]2 years ago

7 0

Answer:

<h2>Hope it helps</h2>

.......⋋✿ ⁰ o ⁰ ✿⋌

rjkz [21]2 years ago

6 0

Answer:

n = 14

Step-by-step explanation:

ΔABC was dilated by a scale factor of 2.

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In a certain area, there are 35 houses to 55 businesses. Write the ratio of houses to

ratelena [41]

Answer:

$\frac{7}{11}$

Step-by-step explanation:

Express the fraction as number of houses over number of businesses, that is

ratio = $\frac{35}{55}$

Divide numerator and denominator by 5 for simplest form

ratio = $\frac{7}{11}$

3 0

2 years ago

**HELP MEEEE!! NEED ANSWERE ASAP!!!!**

Stells [14]

The first one is -8+2 = -6

And the second one is 2 x 2 = 4

3 0

3 years ago

Read 2 more answers

Lin has a scale model of a modern train. The model is created at a scale of 1 to 48

kati45 [8]

Solution 1. 4.896 meters. Sample reasoning: The actual height is 48 times the scaled height. . 4,896 mm is 4.896 m.

102 mm is 0.102 m. The actual train is 48 times 0.102 m. .

2. No. Sample explanation: The modern train needs tracks that are 60 inches apart, because 1 1/4 x 48 =60 . The old tracks are only 54 inches, so they are not wide enough.

Step-by-step explanation:

4 0

3 years ago

You work in the HR department at a large franchise. you want to test whether you have set your employee monthly allowances corre

ra1l [238]

Answer:

1) Null hypothesis: $\mu \leq 500$

Alternative hypothesis: $\mu > 500$

$z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90$

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

$z_{crit}= 2.33$

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:

$p_v =P(z>5.90)=1.82x10^{-9}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

$\bar X=640$ represent the sample mean

$\sigma=150$ represent the population standard deviation

$n=40$ sample size

$\mu_o =500$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Step1:State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:

Null hypothesis: $\mu \leq 500$

Alternative hypothesis: $\mu > 500$

Step 2: Calculate the statistic

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

We can replace in formula (1) the info given like this:

$z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90$

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

$z_{crit}= 2.33$

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value

Since is a right tailed test the p value would be:

$p_v =P(z>5.90)=1.82x10^{-9}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

7 0

3 years ago

Shell charges $2.23 dollars per gallon of gas for refueling vehicles. Assume the number of gallons is your independent variable

sattari [20]

Y=$2.23x
Is there more to the question?

5 0

3 years ago