The decimal approximation for the trigonometric function sin 28°48' is
Given the trigonometric function is sin 28°48'
The ratio between the adjacent side and the hypotenuse is called cos(θ), whereas the ratio between the opposite side and the hypotenuse is called sin(θ). The sin(θ) and cos(θ) values for a given triangle are constant regardless of the triangle's size.
To solve this, we are going to convert 28°48' into degrees first, using the conversion factor 1' = 1/60°
sin (28°48') = sin(28° ₊ (48 × 1/60)°)
= sin(28° ₊ (48 /60)°)
= sin(28° ₊ 4°/5)
= sin(28° ₊ 0.8°)
= sin(28.8°)
= 0.481753
Therefore sin (28°48') is 0.481753.
Learn more about Trigonometric functions here:
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Kulay, there is no such thing as a "step by step answer" here. You seem to want a "step by step solution."
I must assume that by 4/5 you actually meant (4/5) and that by 2/3 you meant (2/3). Then your equation becomes:
(4/5)w - 12 = (2/3)w.
The LCD here is 5*3, or 15, so mult. every term by 15:
12w - 180 = 10w.
Add 180 to both sides, obtaining 12 w - 180 + 180 = 10w + 180.
Then 12w = 10w + 180. Simplifying, 2w = 180. What is w?
Answer:
1, x = 80
2, z = 5.6
3, w = 18
Step-by-step explanation:
the answer is step by step CFE
