(0, -2) and (1, 1) both work in this system of equations.
The best way to find if it is a solution is to look for those points on the graph. When you graph the point, it needs to fall in an area where both lines or shaded or on a solid line.
(0, -2) falls on a solid line.
(1, 1) falls in the double shaded area.
Answer:
Proved
Step-by-step explanation:
Given
<u>Circle C</u>
--- radius
--- center
<u>Circle E</u>
--- center
Required
Prove their similarity
Translate circle C 8 units up;
The rule is:
So, we have:
Translate circle C' 7 units right;
The rule is:
So, we have:
<em>At this point, both circles now have the same center at (4,9)</em>
The next step is to dilate circle E by 4/3
This will only affect radius and not the center of E
The rule is:
So, we have:
-- equal radii
--- equal center
<em>Proved</em>
<span>the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 ) Δ > 0 the equation has two reals solutions : x = (-b±√Δ)/2a</span>
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions
Answer:
1/3
Step-by-step explanation:
51/6 = 51/6
51/2= 5 3/6
= 2/6
Class 1 =$177.90
Class 2 =$159
Class 1
24 tube of paint / $3.35 each
12 brushes/ $1.75 each
17 canvases/$4.50 each
Total cost of paint= $80.40
Total cost of brushes=$21
Total cost of canvases= $76.50
Total spent on class 1 = $177.90
Class 2
20 tubes of paint/$3.35 each
14 brushes/$1.75 each
15 canvases/ $4.50 each
Total cost of paint=$67
Total cost of brushes =$24.50
Total cost of canvases=$67.50
Total spent on class 2 = $159
