All categories

3 years ago

14 - 3c + 8 + c ????

Mathematics

1 answer:

natta225 [31]3 years ago

8 0

Answer:

−2c+22

Step-by-step explanation:

You might be interested in

3/8 of the students in Ms. Mull’s class ride the bus. If there are 24 students in the class, how many students ride the bus?

dsp73

Answer:

9 students

Step-by-step explanation:

To find how many students ride the bus, you must do 3/8 times 24. The word "of" in math means to multiply. 3/8 times 24 equals 9.

3 0

3 years ago

A video of Mr. Satyam’s class discussing mathematical strategies won a STEM award. 8% of the videos won awards. There were 24 aw

LekaFEV [45]

Answer:

There were 300 videos.

Step-by-step explanation:

Since there are 24 videos that got awards, and that's only 8% of the total videos, you put those together. We want the number of 100% of the videos. I would solve this by setting up a ratio and solving for $x$ . This is would look like:

$\frac{24}{8} =\frac{x}{100}$

In order to get to 100, you must multiply 8 by 12.5. Therefore, you can multiply 24 by 12.5 to complete the ratio. That would make the ratio look like:

$\frac{24}{8} =\frac{300}{100}$

Therefore there are 100% of the videos in the contest is 300.

6 0

3 years ago

In which quadrant does the point (18, -18) lie?

kvv77 [185]

It lies in Quadrant 3

4 0

3 years ago

Read 2 more answers

Malaya bought 32 pieces of candy for $16. The next day she returns to buy more candy with $4. How many pieces can she buy

Vanyuwa [196]

she can buy 8 pieces because each candy is 50 cents

8 0

3 years ago

Read 2 more answers

State the vertical asymptote of the rational function. f(x) =((x-9)(x+7))/(x^2-4)

Lubov Fominskaja [6]

$D:x^2-4\not=0\\
D:x^2\not=4\\
D:x\not=-2 \wedge x\not =2\\\\
\displaystyle
\lim_{x\to-2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(-2-9)(-2+7)}{(-2^-)^2-4}=\dfrac{-11\cdot5}{4^+-4}=\dfrac{-55}{0^+}=-55\cdot\infty=-\infty\\
\dfrac{(-2-9)(-2+7)}{(-2^+)^2-4}=\dfrac{-11\cdot5}{4^--4}=\dfrac{-55}{0^-}=-55\cdot(-\infty)=\infty
$

$\displaystyle
\lim_{x\to2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(2-9)(2+7)}{(2^-)^2-4}=\dfrac{-7\cdot9}{4^--4}=\dfrac{-63}{0^-}=-63\cdot(-\infty)=\infty\\
\dfrac{(2-9)(2+7)}{(2^+)^2-4}=\dfrac{-7\cdot9}{4^+-4}=\dfrac{-63}{0^+}=-63\cdot\infty=-\infty\\$

So, the vertical asymptotes are $x=\pm 2$

5 0

4 years ago

Read 2 more answers