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3 years ago

Find 1 2/3 + (-2 1/2)

Mathematics

2 answers:

BabaBlast [244]3 years ago

6 0

2/3 - 1/2 = 1/
6
≅ 0.1666667

Elenna [48]3 years ago

4 0

Answer:

you can use a calculator to find this

Step-by-step explanation:

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Solve for x -6x+3≥21 a. x ≤ -3 b. x ≥ -3 c. x ≤ 3

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3 years ago

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Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA

tekilochka [14]

Step-by-step explanation:

$\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2} }{sinA(1+cosA)} \\\\$

$\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\$ and we have $sin^{2}+cos^{2} =1$

so $\frac{1+1+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2(1+cosA)}{sinA(1+cosA)} \\\\$

$\frac{2}{sinA}$ we have $\frac{1}{sin}=cosec\\$

Finally $2cosecA$

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3 years ago

Let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes. If the random var

jeka57 [31]

Answer:

The parameters of this exponential distribution is $\lambda$ = $\frac{1}{27}$ .

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes.

So, X = time it takes for a person to choose a birthday gift

The probability distribution function of exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} , x >0$ where, $\lambda$ = parameter of distribution.

Now, the mean of exponential distribution is = $\frac{1}{\lambda}$ which is given to us as average value of 27 minutes that means $\lambda = \frac{1}{27}$ .

So, X ~ Exp( $\lambda = \frac{1}{27}$ ) .

Therefore, the parameter of this exponential distribution is $\lambda$ .

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