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nadya68 [22]
3 years ago
14

Find 1 2/3 + (-2 1/2)

Mathematics
2 answers:
BabaBlast [244]3 years ago
6 0
2/3 - 1/2 = 1/
6
≅ 0.1666667
Elenna [48]3 years ago
4 0

Answer:

you can use a calculator to find this

Step-by-step explanation:

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Mrs. King has a stack of papers to grade that contains 12 boy’s papers and 8 girl’s papers. What is the probability that the fir
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Answer:3/5

Step-by-step explanation:

20 papers in total

12 boy papers

12/20

simplified to 3/5

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Hii pls help i’ll give you brainliest if you give a correct answer.
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19.375

Step-by-step explanation:

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Des buys a pack of starbursts that has 3 orange,6 pink , 1 yellow , and 5 red starbursts. She puts the candy in the bowl. If she
Ksivusya [100]

Answer:

3/70

Step-by-step explanation:

3 orange,6 pink , 1 yellow , and 5 red = 15

P(pink) = number of pink/ total = 6/15 = 3/5

Then without putting it back

3 orange,5 pink , 1 yellow , and 5 red = 14

P(yellow) = number of yellow/ total = 1/14

P(pink, no replacement, yellow) = 3/5*1/14 = 3/70

5 0
3 years ago
Which statement is true of this function?
Eduardwww [97]

Answer:

  A.  As the value of x increases, the value of f(x) moves toward a constant

Step-by-step explanation:

An exponential function with a base less than 1 will decay to zero. Here, the exponential has -2 added to it, so the decay is toward the value -2.

An exponential function is defined for all real numbers. This one has a y-intercept of -1.

6 0
3 years ago
The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni
charle [14.2K]

Answer:

(a)77.4bpm

(b)Mean of Sample 1 = 70.3 beats per minute.  

Mean pulse of sample 2 = 70 beats per minute.

(c)

  • The mean pulse rate of sample 1 underestimates the population mean.
  • The mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

(a)Population mean pulse.

The pulse of the nine students which represent the population are:

  • Perpectual Bempah      64
  • Megan Brooks               77
  • Jeff Honeycutt               89
  • Clarice Jefferson           69
  • Crystal Kurtenbach       89
  • Janette Lantka              65
  • Kevin McCarthy             88
  • Tammy Ohm                  69
  • Kathy Wojdya                 87

\text{Population Mean} =\dfrac{64+77+89+69+89+65+88+69+87}{9} \\=\dfrac{697}{9} \\\\=77.44

The population mean pulse is approximately 77.4 beats per minute.

(b)Sample 1: {Janette,Clarice,Megan}

  • Janette: 65bpm
  • Clarice: 69bpm
  • Megan: 77bpm

Mean of Sample 1

\text{Sample 1 Mean} =\dfrac{65+69+77}{3} \\=\dfrac{211}{3} \\\\=70.3

Sample 2: {Janette,Clarice,Megan}

  • Perpetual: 64bpm
  • Clarice: 69bpm
  • Megan: 77bpm

Mean of Sample 2

\text{Sample 2 Mean} =\dfrac{64+69+77}{3} \\=\dfrac{210}{3} \\\\=70

The mean pulse of sample 1 is approximately 70.3 beats per minute.  

The mean pulse of sample 2 is approximately 70 beats per minute.

(c)

  • The mean pulse rate of sample 1 underestimates the population mean.
  • The mean pulse rate of sample 2 underestimates the population mean.
7 0
3 years ago
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