Ask question

Ask question

All categories

sergij07 [2.7K]

3 years ago

5

What is the domain of the graph?

1 answer:

zzz [600]3 years ago

5 0

Answer:

It is a x-axis

Step-by-step explanation:

horizontal line

You might be interested in

Find the LCM of<br> 18 and 20.

Gala2k [10]

Answer: 180

Multiples of 18: 18, 36, 54, 72, 90, 108, 126, 144, 162, 180

Multiples of 20: 20, 40, 60, 80, 100, 120, 140, 160, 180

6 0

3 years ago

Which number are factors of 4? 9,7,6,1 select al that apply

kifflom [539]

Answer:

1

Step-by-step explanation:

the factors of 4 are 1, 2, 4

1 x 4 = 4

2 x 2 = 4

4 x 1 = 4

4 0

3 years ago

Read 2 more answers

Marlins Marble Jar Had 36 Red Marbles and 64 blue marbles what was the ratio of red marbles to blue marbles in the jar

slamgirl [31]

36:64
Divide each by 4 to get it in simplest form
You get 9:16 as your answer

7 0

4 years ago

Please help I’m a bit confused on this I appreciate answers!

Afina-wow [57]

Answer:

$(2x^3)^3=8\cdot x^{9}$

Step-by-step explanation:

<u>Properties of Exponents</u>

The property called Power to a Power shows us how to simplify expressions of the type:

$(x^n)^m=x^{n*m}$

Similarily the property called Power of a product simplifies expressions like:

$(x.y)^n=x^n.y^n$

The company mentioned in the question uses the expression

$(2x^3)^3$

millimeters per second to calculate the maximum capacity of a photocell with an area of x^3 square millimeters.

First, use the power of a product property:

$(2x^3)^3=2^3\cdot (x^3)^3$

Now use the power to a power property:

$(2x^3)^3=2^3\cdot x^{3*3}$

Operate:

$\mathbf{(2x^3)^3=8\cdot x^{9}}$

5 0

3 years ago

Use the distance formula to determine the distance between (-8,10) and (-6,7)

hjlf

Answer:

Distance: $\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where:

$d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$
$(x_1,y_1)$ are the coordinates of the first point
$(x_2,y_2)$ are the coordinates of the second point

We are given that:

$(x_1,y_1)=(-8,10)$
$(x_2,y_2)=(-6,7)$

To determine the value of our distance, $d$ , we plug in our given information into the formula and solve for

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-6-(-8))^2+(7-10)^2}$

$d=\sqrt{(-6+8)^2+(-3)^2}$

$d=\sqrt{(2)^2+(-3)^2}$

$d=\sqrt{4+9}$

$d=\sqrt{13}$

Therefore, the distance between $(-8,10)$ and $(-6,7)$ is $\sqrt{13}$ units.

See the attached graph for a visual.

5 0

3 years ago