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3 years ago

3x+4=8y-3 5x+1=10y-4

Mathematics

1 answer:

dsp733 years ago

4 0

Answer:

x-3 and y=2

Step-by-step explanation:

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Graph the hyperbola with equation quantity x minus 1 squared divided by 49 minus the quantity of y plus 3 squared divided by 9 e

Sliva [168]

Answer:

See attached diagram

Step-by-step explanation:

You are given the equation of hyperbola

$\dfrac{(x-1)^2}{49}-\dfrac{(y+3)^2}{9}=1$

From this equation,

the center of hyperbola is at point (1,-3);
the real semi-axes $a^2=49\Rightarrow a=7;$
the imaginary semi-axes $b^2=9\Rightarrow b=3.$

Draw two parallel lines x=1 and y=-3 (they intersect at the center of hyperbola), then on horizontal line match two hyperbola's vertices (7 units to the left and 7 units to the right from the center). Then draw two branches of hyperbola (one in negative direction and one in positive direction).

3 0

4 years ago

Solve For Q q/10=4 Please Answer This For Me. Thanks.

Maurinko [17]

$\frac{q}{10} = 4\\q = 4 * 10\\q = 40$

Answer: 40.

3 0

3 years ago

Read 2 more answers

Find the missing number 1:2 = 3: ____

irina [24]

1:2 = 3: 6

hope it helps

3 0

3 years ago

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It is known that a cable with a cross-sectional area of 0.300.30 sq in. has a capacity to hold 2500 lb. If the capacity of the

vesna_86 [32]

Answer:

0.84 square in

Step-by-step explanation:

Since the capacity of the cable is proportional to its cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold

2500 / 0.3 = 8333.33 lb/in

To old 7000 lb it the cross-sectional area would need to be

7000 / 8333.33 = 0.84 square in

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3 years ago

Read 2 more answers

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

85% confidence level

So $\alpha = 0.15$ , z is the value of Z that has a pvalue of $1 - \frac{0.15}{2} = 0.925$ , so $Z = 1.44$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with $M = 0.03, \pi = 0.21$