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3 years ago

Brainliest! Correct answer! Need to pass...

Mathematics

1 answer:

iren2701 [21]3 years ago

6 0

Answer:

it is the 3rd one

Step-by-step explanation:

I think it is

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Use the formula

natita [175]

A=bh
108=<span>12*h
9in=h
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3 years ago

What is −3/5 as a decimal?

lidiya [134]

The answer will be.35

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3 years ago

Read 2 more answers

Plsss helppppp I’ll mark u brainlist no links pls

Basile [38]

Step-by-step explanation:

you flip it from the line, match the letters (Z woube be C, X would be A, etc.) and then writw the new coordinates

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3 years ago

The amount y ( in grams) of a radioactive isotope phosphorus-32 remaining after t days is y=a(0.5)^t/14, where a is the initial

Neko [114]

Answer:

Step-by-step explanation:

The way I figured this out is to just pick some starting values for the grams of this element and plug them into the formula using t = 1 day and seeing how much is left. I chose 2 different starting amounts and came up with the same percentage each time, so it must be correct! Here's what I did:

First I chose a starting amount, a, of 10 grams. Plugging into the formula:

$y=10(.5)^{\frac{1}{14} }$

and got that the amount LEFT was 9.5 grams

Then I chose a starting amount, a, of 20 grams. Plugging into the formula:

$y=20(.5)^{\frac{1}{14}}$

and got that the amount LEFT was 19 grams.

I then asked the algebraic question,"What percent of 10 is 9.5?" which translates to

x% * 10 = 9.5 and

x = 95% (that's the amount left as a percentage).

and

x% * 20 = 19 and

x = 95%

Since both of those came out the same, that tells me that after 1 day there is still 95% of the element remaining, so 5% decays each day.

5 0

3 years ago

Solve the equation for Imaginary Numbers 1/2(x^2+40)=-12

Nimfa-mama [501]

Answer:

8i and -8i

Step-by-step explanation:

Move everything into the left-hand side to get a quadratic equation:

$\frac{1}{2}(x^2+40)=-12\\\frac{1}{2}x^2+20=-12\\\frac{1}{2}x^2+32=0$

Solve for x using the quadratic formula:

$\frac{1}{2}x^2+32=0\\x=\frac{-b\±\sqrt{b^2-4ac}}{2a}\\x=\frac{-(0)\±\sqrt{0^2-4(\frac{1}{2})32}}{2(\frac{1}{2})}\\x=\±\sqrt{-64}\\x=\±8i$

The two imaginary solutions for the equation are 8i and -8i.

3 0

3 years ago