Answer:
Two straight lines with slopes m and m' are parallel when m = m'
Two straight lines with slopes m and m' are perpendicular when m × m' = - 1.
Step-by-step explanation:
Let us assume that the two non-vertical lines in the slope-intercept form are
y = mx + c ........... (1) and
y = m'x + c' ............ (2)
If those two lines are parallel then we can say the slope of them will be the same i.e. m = m'
Now, if given two straight lines (1) and (2) are perpendicular to each other and neither of them is parallel to the axes, then we can write m × m' = - 1. (Answer)
The answer is -8
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Explanation:
There are two ways to get this answer
Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8
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The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4
g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8
Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8
Regardless of which method you use, the answer is -8
When you divide two fractions, you're actually multiplying one of them by the reciprocal of the other. First, find the reciprocal of the second fraction by flipping it upside down. Then, multiply it by the first fraction. (Numerator x numerator and denominator x denominator)
÷
Replace the second fraction with it's reciprocal
x
Multiply (-7 x 3 and 12 x 2)
Both 21 and 24 are divisible by three, so divide them by 3
The answer is 36
lmk if you need steps
The answer would be
4
5
6
Yes
