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2 years ago

Can somebody solve this

Mathematics

1 answer:

Gemiola [76]2 years ago

4 0

The answer is 36
lmk if you need steps

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Please help me with the below question.

Snezhnost [94]

6a. By the convolution theorem,

$L\{t^3\star e^{5t}\} = L\{t^3\} \times L\{e^{5t}\} = \dfrac6{s^4} \times \dfrac1{s-5} = \boxed{\dfrac5{s^4(s-5)}}$

6b. Similarly,

$L\{e^{3t}\star \cos(t)\} = L\{e^{3t}\} \times L\{\cos(t)\} = \dfrac1{s-3} \times \dfrac s{1+s^2} = \boxed{\dfrac s{(s-3)(s^2+1)}}$

7. Take the Laplace transform of both sides, noting that the integral is the convolution of $e^t$ and $f(t)$ .

$\displaystyle f(t) = 3 - 4 \int_0^t e^\tau f(t - \tau) \, d\tau$

$\implies \displaystyle F(s) = \dfrac3s - 4 F(s) G(s)$

where $g(t) = e^t$ . Then $G(s) = \frac1{s-1}$ , and

$F(s) = \dfrac3s - \dfrac4{s-1} F(s) \implies F(s) = \dfrac{\frac3s}{\frac{s+3}{s-1}} = 3\dfrac{s-1}{s(s+3)}$

We have the partial fraction decomposition,

$\dfrac{s-1}{s(s+3)} = \dfrac13 \left(-\dfrac1s + \dfrac4{s+3}\right)$

Then we can easily compute the inverse transform to solve for f(t) :

$F(s) = -\dfrac1s + \dfrac4{s+3}$

$\implies \boxed{f(t) = -1 + 4e^{-3t}}$

6 0

1 year ago

Me wit filtersssssssssssssss

N76 [4]

Answer:

Your cute. Keep being you!

Step-by-step explanation:

6 0

2 years ago

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A recipe for banana bread requires 3 cups of bananas for every 1 1/2 cups of sugar used. At this rate how many cups of sugar sho

mr Goodwill [35]

Answer:

The answer is 1 cup of sugar

Step-by-step explanation:

x = 2 x 1.5/3

x = 3/3

x = 1 cup of sugar

hope it helps!

4 0

3 years ago

Find the angles a, b, c and d.

Alborosie

A=180-79= 101°

B=75°

C=83°

D=101°

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3 years ago

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Fill in the table using this function rule. y= -6x+1

Eddi Din [679]

Take a picture of the table

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3 years ago