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aliina [53]
3 years ago
5

1. If two nonvertical lines are parallel, what do we know about their slopes? If two lines are perpendicular and neither is para

llel to an axis, what do we know about their slopes? Why must the lines be nonvertical?
Mathematics
1 answer:
yanalaym [24]3 years ago
6 0

Answer:

Two straight lines with slopes m and m' are parallel when m = m'

Two straight lines with slopes m and m' are perpendicular when m × m' = - 1.

Step-by-step explanation:

Let us assume that the two non-vertical lines in the slope-intercept form are

y = mx + c ........... (1) and  

y = m'x + c' ............ (2)

If those two lines are parallel then we can say the slope of them will be the same i.e. m = m'

Now, if given two straight lines (1) and (2) are perpendicular to each other and neither of them is parallel to the axes, then we can write m × m' = - 1. (Answer)

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I can’t figure out how to use the zeros in the polynomial. Please explain
Temka [501]

Answer:

a) P (x) = (x + 3) (x-1) (x-4)

b) P (x) = (2x + 5) (5x - 4) (x-6)

c) P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

P (x) = (2x + 5) (5x - 4) (x-6)

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

8 0
3 years ago
Write an equation of a line in point-slope, slope-intercept, and standard form that has
Inga [223]

Answer:

(a) y + 4x - 14 = 0

(b) y = -4x + 14

(c) y + 4x = 14

Step-by-step explanation:

The formula for calculating the equation of line in point - slope form is given as :

y-y_{1}  = m(x-x_{1} )

where m is the slope

Given from the question :

m = - 4

x_{1} = 2

y_{1} = 6

Substituting into the formula , we have :

y - 6 = - 4(x - 2)

y - 6 = -4x + 8

y + 4x - 6 - 8 = 0

y + 4x - 14 = 0

Therefore :

(a) the equation of the line in point - slope form is y + 4x - 14 = 0

(b) to write it in slope - intercept form , we will make y the subject of the formula , which will give : y = -4x + 14

(c) the equation of line in standard form is ; y + 4x = 14

5 0
3 years ago
Solve the inequality for x.
Taya2010 [7]

Answer:

+10 on both sides so

X+10-(10)>14-(10)

x>4

3 0
3 years ago
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Evaluate x+y+z for x=2, y=-3, Z= 4.
tamaranim1 [39]

Answer:

5

Step-by-step explanation:

4 0
3 years ago
The product of 5/2 and 13/4 is greater than , less than, or equal to 13/4
Bas_tet [7]

Answer:

the product is greater than 13/4

Step-by-step explanation:

5/2 x 13/4 = 8.125

13/4= 3.25

8.125>3.25

8 0
3 years ago
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