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anyanavicka [17]
3 years ago
6

Prove that segment ST is parallel to segment RQ then x=12

Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

x=12

Step-by-step explanation:

x=12

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A bridge hand in which there is no card higher than a nine is called a Yarborough. Specify an appropriate sample space and deter
Vilka [71]

Answer:

The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.

Step-by-step explanation:

The number of ways you  can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.

Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.

This leads to the same value for the desired probability of a Yarborough:

32P13 / 52P13  = 0.000547.

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4 years ago
If you roll two fair six sided dice what is the probability that at least one die shows a three
Veronika [31]

Answer:

idc

Step-by-step explanation:

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4 years ago
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Which statement is false? A. (−2)×5<(−20) B. (−2)×(−5)>(−25) C. 2×5>(−25) D. 2×(−5)<20
natali 33 [55]

Answer:

(−2)×5<(−20)

Step-by-step explanation:

Evaluating the options given :

(−2)×5<(−20)

Open the bracket

- 10 < - 20 (false) ` This expression isn't true

(−2)×(−5)>(−25)

Open the bracket

10 > - 25 (true)

2×5>(−25)

Open the bracket

10 > - 25 (true)

2×(−5)<20

Open the bracket

- 10 < 20

4 0
3 years ago
Summary of Arrow of Destiny
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3 years ago
Solve. 3(x-6)-2(2x+3)=14
coldgirl [10]

Answer:

x=-38

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x−6)−2(2x+3)=14

(3)(x)+(3)(−6)+(−2)(2x)+(−2)(3)=14(Distribute)

3x+−18+−4x+−6=14

(3x+−4x)+(−18+−6)=14(Combine Like Terms)

−x+−24=14

−x−24=14

Step 2: Add 24 to both sides.

−x−24+24=14+24

−x=38

Step 3: Divide both sides by -1.

−x

−1

=

38

−1

x=−38

5 0
3 years ago
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