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anyanavicka [17]
3 years ago
6

Prove that segment ST is parallel to segment RQ then x=12

Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

x=12

Step-by-step explanation:

x=12

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4(x-2)=2(x+7) helpp pleasee
Talja [164]

4x-8=2x+14

subtract 2x on both sides and add 8 on both sides so x=11

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3 years ago
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Question 5: prove that it’s =0
mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that \cos(\frac{2}{x}) is a variable number between -1 and 1 (inclusive).

This means that -1 \le \cos(\frac{2}{x}) \le 1.

x^4 \ge 0 for all value x. So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

By squeeze theorem, if  -x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

and \lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L, then we can also conclude that \im_{x \rightarrow} x^4\cos(\frac{2}{x})=L.

So we can actually evaluate the "if" limits pretty easily since both are continuous  and exist at x=0.

\lim_{x \rightarrow 0}x^4=0^4=0

\lim_{x \rightarrow 0}-x^4=-0^4=-0=0.

We can finally conclude that \lim_{\rightarrow 0}x^4\cos(\frac{2}{x})=0 by squeeze theorem.

Some people call this sandwich theorem.

6 0
3 years ago
Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted
Misha Larkins [42]

Answer:

\frac{15}{28}  is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red = 3 + 5 = 8

Probability of getting blue = \frac{3}{8}

Probability of not getting a blue =\frac{5}{8}

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

<u>First Draw Blue, Second Draw Not Blue:</u>

1st Draw: P(Blue) = \frac{3}{8}

2nd Draw: P(Not\:Blue)=\frac{5}{7}  (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

P(Event)=\frac{3}{8}\cdot \frac{5}{7}=\frac{15}{56}

<u>First Draw Not Blue, Second Draw Not Blue:</u>

1st Draw: P(Not\:Blue)=\frac{5}{8}

2nd Draw: P(Not\:Blue)=\frac{3}{7}  (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

P(Event)=\frac{5}{8}\cdot \frac{3}{7}=\frac{15}{56}

To get the probability of exactly one blue, we add both of the events:

\frac{15}{56}+\frac{15}{56}=\frac{15}{28}

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3 years ago
You are in charge of purchasing donuts and chocolate milk for a school activity. Find the cost of donuts and chocolate milk at y
inna [77]
An equation in standard form looks like Ax + By = C.

Let C = 80

Take it from here.
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Can someone complete the square??
ira [324]

THE ANSWER IS..... X1= -6 & X2=0

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