[19] x2 [38]x2[76]x2[152]x2[304] this is the answer
If u want to know how I get it than divide the number in the box by 2 than u will get the first two missing number than last u divide 152 by 2 to get the last missing number
17.5 is bigger.1\6 is small.
In order to sole the problem you need to create an equation to model what you are trying to do.
You end up with an equation looking like
25000*0.95^t
25000 is the starting value when t=0
95% is the amount remaining after the 5% decay
0.95 is being raised to the power of t to determine how many times it has decayed
When t=3 the equation should be
25000*0.95^3=21434.375
Answer:
20%.
Step-by-step explanation:
That is (60 - 50) / 50
= 10/50
= 1/5
To convert to a percent we multiply by 100:
= 20%.
The answer is: [C]: " ⁷/₆ " .
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Note:
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(5/3) - (1/2) = ? ;
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The LCD (lowest common denominator) of "2 and 3" is "6" ;
So we need to rewrite EACH fraction in the problem as a fraction with "6" in the denominator ;
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(5/3) = (?/6) ? ; (6÷3=2) ; (5/3) = (5*2)/(3*2) = 10/6 ;
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(1/2) = (?/6) ? ; (6÷2=3) ; (1/2) = (1*3)/(2*3) = 3/6 ;
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Rewrite the problem: " (5/3) - (1/2) " ; as:
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10/6 - 3/6 ;
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10/6 - 3/6 = (10 - 3) / 6 = (7/6) = 1 ⅙ .
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The answer is: " ⁷/₆ " ; or, write as: " 1 ⅙ " ; which corresponds to:
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Answer choice: [C]: " ⁷/₆ " .
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