Answer:37.2 sec
Step-by-step explanation:
Given
Joel takes 81 sec for 14 mile long track
speed of joel 
mi/min=10.37 mi/min
Jason takes 69 sec for 14 mi track
so jason speed is 
if both starts from same spot in opposite direction then
where x is distance covered by Joel
then x=6.44 miles
therefore time required
Answer:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Step-by-step explanation:
We want to evaluate ![[11.5-(2.5*3)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2)
Let us evaluate within the parenthesis first:
![[11.5-(2.5*3)]^2=[11.5-(7.5)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-%287.5%29%5D%5E2)
![\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2](https://tex.z-dn.net/?f=%5Cimplies%20%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-7.5%5D%5E2)
We again subtract within the bracket to obtain:
![[11.5-(2.5*3)]^2=[4]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B4%5D%5E2)
This finally gives us:
Answer:
8. x = 16
9. x = 10
14.
m ∠RSU = 130°
m ∠UST = 50°
15.
m ∠RSU = 124°
m ∠UST = 56°
Step-by-step explanation:
8.
Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF
That is , (x + 15)° = 31°
x = 31 - 15 = 16
9.
Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF
That is ,
(6x - 4)° = 56°
6x = 56 + 4
6x = 60
x = 10
14.
13x + 5x = 180° [straight line angles ]
18x = 180
x = 10
m ∠RSU = 130°
m ∠UST = 50°
15.
4x + 12 + 2x = 180° [ straight line angles]
6x = 180 - 12
6x = 168
x = 28
m ∠RSU = 4(28) + 12 = 112 + 12 = 124°
m ∠UST = 2(28) = 56°
The answers are E.) y-int is (0,4), F.) domain of F(x) is all rel numbers , and C.) it is increasing
