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erik [133]
3 years ago
14

What is two hundred and forty dived by six

Mathematics
2 answers:
Serggg [28]3 years ago
4 0
The answer to that is 40.
8_murik_8 [283]3 years ago
3 0
The answer is 24.166
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F(x) = 5x – 2<br><br> slope of f =
devlian [24]

Answer:

? we dint know

Step-by-step explanation:

3 0
2 years ago
High blood pressure has been identified as a risk factor for heart attacks and strokes. The proportion of U.S. adults with high
KengaRu [80]

Answer:

1. It is not appropriate to use the normal curve, since np = 7.4 < 10.

2. The probability that more than 32% of the people in this sample have high blood pressure is 0.0033 = 0.33%.

Step-by-step explanation:

Binomial approximation to the normal:

The binomial approximation to the normal can be used if:

np >= 10 and n(1-p) >= 10

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The proportion of U.S. adults with high blood pressure is 0.2. A sample of 37 U.S. adults is chosen.

This means, respectively, that p = 0.2, n = 37

Is it appropriate to use the normal approximation to find the probability that more than 48% of the people in the sample have high blood pressure?

np = 37*0.2 = 7.4 < 10

So not appropriate.

It is not appropriate to use the normal curve, since np = 7.4 < 10.

Part 2:

Now n = 82, 82*0.2 = 16.4 > 10, so ok

Mean and standard deviation:

By the Central Limit Theorem,

Mean \mu = p = 0.2

Standard deviation s = \sqrt{\frac{0.2*0.8}{82}} = 0.0442

Find the probability that more than 32% of the people in this sample have high blood pressure.

This probability is 1 subtracted by the pvalue of Z when X = 0.32. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.32 - 0.2}{0.0442]

Z = 2.72

Z = 2.72 has a pvalue of 0.9967.

1 - 0.9967 = 0.0033

The probability that more than 32% of the people in this sample have high blood pressure is 0.0033 = 0.33%.

5 0
4 years ago
Whats the percent change from 100 to 140​
Dahasolnce [82]

Answer:

40%

Step-by-step explanation:

8 0
3 years ago
Find the area of this trapezoid. Be sure to include the correct unit in your answer. Continue 13 cm 20 cm 8 cm 5 cm 0 0/0 08 cm
kodGreya [7K]

Given:

• Upper Base of trapezoid = 8 cm

,

• Lower base = 20 cm

,

• Length of one leg (also height) = 5 cm

,

• Length of other leg = 13 cm

Let's find the area of the trapezoid.

To find the area of the trapezoid, apply the formula:

A=\frac{a+b}{2}*h

Where:

A is the area

a is the length of upper base = 8 cm

b is the length of the lower base = 20 cm

h is the height = 5 cm

Plug in the values for a, b, and h to find the area, A:

\begin{gathered} A=\frac{8+20}{2}*5 \\  \\ A=\frac{28}{2}*5 \\  \\ A=14*5 \\  \\ A=70\text{ cm}^2 \end{gathered}

Therefore, the area of the trapezoid is 70 cm^2

8 0
1 year ago
Which of the following is an example of the law of detachment?
Xelga [282]
A is an example of the law of detachment
6 0
3 years ago
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