Answer:
For this case we have the following info related to the time to prepare a return

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean
is given by:
And the standard deviation would be:

And the best answer would be
b. 2 minutes
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Solution to the problem
For this case we have the following info related to the time to prepare a return

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean
is given by:
And the standard deviation would be:

And the best answer would be
b. 2 minutes
Answer:
Money raised($)= 6n-50
Step-by-step explanation:
they plan to sell the hats for $10. each hat $4 to make and they spend $50 for advertising.
If their are no number of hats
Cost = 50+4n
Money gotten from the n number of hats= 10(n)
If they are to make profit, the money gotten from the sales of hats should be bigger than the total cost
Money raised = money from sales- cost
Money raised= 10n -4n-50
Money raised($)= 6n-50
Answer:
The answer is C.
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
AB = √(-4)² + (-3)²
AB = √ 16 + 9
AB = √ 25
AB = 5
AD = 4 ; DC = 4 ; BC = 7
Perimeter = 5 + 4 + 4 + 7 = 20 units