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4 years ago

12

Let y = In x and V = lny. Write Inyx in terms of u and v.

1 answer:

weqwewe [10]4 years ago

6 0

Answer:

v + u

Step-by-step explanation:

Using the rule of logarithms

log x + log y ⇔ log xy

Given

ln yx, then

ln yx = ln y + ln x = v + u

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Ashley had a summer lemonade stand where she sold small cups of lemonade for $1.25 and large cups for $2.50. if ashley sold a to

Levart [38]

The answer is 98 small and 57 large cups.

s - the number of small cups
l - the number of large cups

<span>Ashley sold a total of 155 cups: s + l = 155
</span><span>Ashley earned</span><span>for $265: 1.25 * s + 2.50 * l = 265

</span>s + l = 155
1.25 * s + 2.50 * l = 265
________
s = 155 - l
1.25 * s + 2.50 * l = 265
________
1.25 * (155 - l) + 2.50 * l = 265
193.75 - 1.25 * l + 2.50 * l = 265
193.75 + 1.25 * l = 265
1.25 * l = 265 - 193.75
1.25 * l = 71.25
l = 71.25 / 1.25
l = 57

______
s = 155 - l
l = 57

s = 155 - 57
s = 98

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3 years ago

What is the solution to the equation 41/5 =15-(2x+3)

likoan [24]

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4 years ago

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Solve the following quadratic equations by any method. The solutions are:

Nataly_w [17]

Answer:

Option C .

Step-by-step explanation:

We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

$\longrightarrow f(x) = x^2-12x +32$

Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

$\longrightarrow f(x) = 0\\$

$\longrightarrow x^2-12x + 32=0$

Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>

$\longrightarrow x^2-8x - 4x +32=0\\$

$\longrightarrow x(x-8)-4(x-8)=0\\$

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$\longrightarrow x = 8 \qquad x = 4$

$\longrightarrow \underline{\underline{\boldsymbol{ x = 8,4}}}$

<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>.</u>

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2 years ago

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