Answer:
3) (98.08, 124.16)
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 111.12
Standard deviation = 13.04
Calculate an interval that is symmetric around the mean such that it contains approximately 68% of fines.
68% of the fines are within 1 standard deviation of the mean speed. So
From 111.12 - 13.04 = 98.08 to 111.12 + 13.04 = 124.16
The interval notation in the smallest value before the highest value.
So the correct answer is:
3) (98.08, 124.16)
Answer:
P( sum is prime )= 73/216
Step-by-step explanation:
The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.
P(sum=3)=1/216, P(sum=5)=6/216, P(sum=7)=15/216, P(sum=11)=27/216, P(sum=13)=21/216, P(sum=17)=3/216.
The final probability will be sum of the above given probabilities.
Hence P( sum is prime )= 73/216
1x + 4y = 11 ⇒ 5x + 20y = 55
5x - 7y = -10 ⇒ <u>5x - 7y = -10</u>
<u>27y</u> = <u>65</u>
27 27
y = 2¹¹/₂₇
x + 4(2¹¹/₂₇) = 11
x + 8²²/₂₇ = 11
<u> - 8²²/₂₇ - 8²²/₂₇
</u> x = 2⁵/₂₇
(x, y) = (2⁵/₂₇, 2¹¹/₂₇)
Answer:
since 5.46 is equal to 5.5...
I think the answer is the first one
