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Helen [10]
3 years ago
5

Estimate the value of √70 to the nearest integer. Describe your process.

Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0

Answer:

\large\boxed{\sqrt{70}\approx8}

Step-by-step explanation:

\text{We know:}\\\\\sqrt{a}=b\iff a^2=b,\ \text{for}\ a\geq0\ \wedge\ b\geq0\\\\5^2=25

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V8 to the nearest tenth is about ?
777dan777 [17]
\sqrt[]{8}\approx2.8

6 0
1 year ago
The center of a circle lies on the line y = 4x + 1 and is tangent to the x-axis at (−3,0) . What is the equation of the circle i
Hunter-Best [27]

Answer:

(x+3)^2+(y+11)^2=121

Step-by-step explanation:

Consider a sketch of the problem as shown in the picture, where:

  • Blue line is given by y = 4x + 1.
  • Point B is the center of the circle.
  • Point A is (-3, 0).

Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.

So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.

Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by

(x-h)^2+(y-k)^2=r^2

then with h = -3, k = -11 and r= 11, the equation of our circle is

(x+3)^2+(y+11)^2=121

5 0
3 years ago
What is the product of 1/4 and -5/12
blsea [12.9K]
ASWER.

1/6


FIRST

12 IS THE LOWEST COMMON DENOMINATOR


SECOND

1\3
4/3
=-5/12


THIRD 3 -5/12
= -2/12
=1/6
6 0
3 years ago
7,243 ÷ 4.<br><br> What is the remainder?
Sveta_85 [38]
Divested using long division
1810 r 3
4 0
3 years ago
florida received 15 inches of rainfall in 3 months of the year. If the state receive 4.25 each month until the end of the year,
kherson [118]
Since there are 12 months in there year and there have already been 3 months there are 9 left

we need to multiply 4.25 by 9 and then add the first 15 inchess

4.25 times 9 = 38.25+15 = 53.25

Florida will recieve 53.25 inches of rain

I hope I've helped!

3 0
3 years ago
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