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2 years ago

9+g+6g–3 a n s w e r p l e a s e

Mathematics

2 answers:

Mars2501 [29]2 years ago

5 0

Answer:

6+7g

Step-by-step explanation:

9+g+6g-3=9-3+g+6g=6+g+6g=6+7g

Alex_Xolod [135]2 years ago

4 0

If you are being asked to simplify, just combine like terms; such as, all the g’s and all the numbers so, your answer should look something like: 7g+6

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What dose this = to? triangles = to 180 buts all i know

lara31 [8.8K]

7. Straight lines are also = to 180°

If you look at the diagram, when you add the two angles together, they form a straight line.

Since the angles add up to 180°, you can do:

(x + 25)° + (4x + 5)° = 180°

x + 25 + 4x + 5 = 180 Combine like terms

5x + 30 = 180 Subtract 30 on both sides

5x = 150 Divide 5 on both sides

x = 30

3 0

2 years ago

Examine the following graph of a line. Which equation correctly represents the line in slope-intercept form?

Xelga [282]

Answer:

-8 -8

Step-by-step explanation:

Because it is the most reasonable

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2 years ago

A cereal mixture contains Almond, Wheat, and Corn in the ratio of 3:5:7. What amount of this mixture contains 9 kilograms of Alm

Mice21 [21]

The total cereal mixture is 45 kilograms

Solution:

Given that, cereal mixture contains Almond, Wheat, and Corn in the ratio of 3:5:7

Therefore,

Almond : Wheat : Corn = 3 : 5 : 7

Let the almond present be 3x

Let the wheat present be 5x

Let the corn present be 7x

Therefore,

Total cereal mixture = 3x + 5x + 7x

Total cereal mixture = 15x

Given that mixture contains 9 kg of almond

Almond = 9

We know that,

Almond present = 3x

3x = 9

x = 3

Therefore,

Total cereal mixture = 15x = 15(3) = 45

Thus total cereal mixture is 45 kilograms

3 0

3 years ago

What is the area of a cross section that is parallel to face CDHG ?

Dennis_Churaev [7]

Answer: Area of cross section that is parallel to face CDHG is 432 cm².

Step-by-step explanation:

Since we have given that

There is a cross section that is parallel to face CDHG.

So, Length of cross section would be 36 cm

Width of cross section would be 12 cm.

So, Area of cross section would be

$Length\times breadth\\\\=36\times 12\\\\=432\ cm^2$

Hence, Area of cross section that is parallel to face CDHG is 432 cm².

8 0

2 years ago

Read 2 more answers

Last year the manager of a health care facility served 36,500 dinners. The manager estimates an increase of 5% in the number of

EastWind [94]

Answer:

38,325 dinners.

Step-by-step explanation:

We have been given that last year the manager of a health care facility served 36,500 dinners. The manager estimates an increase of 5% in the number of dinners to be served next year.

The estimated number of dinners next year would be 36,500 plus 5% of 36,500.

$36,500+(\frac{5}{100}\times 36,500)$

$36,500+(0.05\times 36,500)$

$36,500+1,825$

$38,325$

Therefore, 38,325 dinners will be served next year.

6 0

3 years ago