Given:
Side length of base = 8
Slant height = 6
To find:
The surface area of the square pyramid.
Solution:
Surface area:
where A is the area of base
p is the perimeter of base
s is the slant height
Area of base (A) = 8 × 8
= 64
Perimeter of base(P) = 4 × 8
= 32
Substitute these in the formula:
The surface area of the square pyramid is 160 unit².
The perimeter of a rectangle is all sides added up, so length + length + width + width.
L = length
W = width
then the perimeter is L+L+W+W, or 2L + 2W, or 2(L+W).
what's the length? well, is just
2(27).
Answer:x = -8
Step-by-step explanation:
I got you
Step-by-step explanation:
y=-2/3x-2
Answer:
<em>615.44m²</em>
Step-by-step explanation:
The base of the silo is a circle
Rea of the base of the silo = πr²
r is the radius of the silo
Given
radius r = 14m
Area of the base of the silo = π(14)²
Area of the base of the silo = 3.14(196)
Area of the base of the silo = 615.44
<em>Hence the area of the base of the silo is 615.44m²</em>
