Answer:
g(4) = 7 and f(g(4)) = 43
Step-by-step explanation:
First find g:
g(x) = 3x-5
g(x) = 3(4) - 5
g(x) = 12 - 5
g(x) = 7
Plug in:
f(g(4))
f(7)
Now, find f:
7^2 - 7 + 1
49 - 7 + 1
42 + 1
f(x) = 43
-10v^9+8v^6+2v^5
10=5*2
8=2^3
2=2
The common factor is 2 and its least exponent is 1
The least exponent for the variable v is 5
Then, the GFC of the polynomial is 2v^5
Factoring:
2v^5 [ -(10v^9)/(2v^5)+(8v^6)/(2v^5)+(2v^5)/(2v^5) ] =
2v^5 (-5v^(9-5)+4v^(6-5)+1) =
2v^5 (-5v^4+4v+1)
Questions (contd)
(a) For what amount of driving do the two plans cost the same?
(b) What is the cost when the two plans cost the same?
Answer:
(a) 100 miles
(b) $65
Step-by-step explanation:
Given
Plan 1:

per mile
Plan 2:

per mile
Solving (a): Number of miles when both plans are equal
Represent the distance with x and the cost with y
So:
Plan 1:

Plan 2:

To solve (a), we equate both plans together; i.e.


Collect Like Terms


Solve for x


Hence, 100 mile would cost both plans the same
Solving (b): Cost when both plans are the same:
In this case, we simply substitute 100 for x in any of the y equation.




<em>Hence, the amount is $65</em>
3x + 4 = x+ 8 > 3x - x = 2x > 2x + 4 = 8 > 8 - 4 = 4 > 2x / 2 crosses out > 4 / 2 = 2 > x=2
2y + 5 = y + 7 > 2y - y = y > y+ 5 = 7 > 7-5= 2 > y=2
the perimeter of the kite is 4