Answer:
<h2>2. (0, -4)</h2>
Step-by-step explanation:
![y=4x-4\\\\\text{Substitute the coordinates of each points to the equation}\\\text{and check the equality.}\\\\1.\ (0,\ 4)\to x=0,\ y=4\\\\4=4(0)-4\\4=0-4\\4=-4\qquad\bold{FALSE}\\\\2.\ (0,\ -4)\to x=0,\ y=-4\\\\-4=4(0)-4\\-4=0-4\\-4=-4\qquad\bold{TRUE}\\\\3.\ (-4,\ 0)\to x=-4,\ y=0\\\\0=4(-4)-4\\0=-16-4\\0=-20\qquad\bold{FALSE}\\\\4.\ (4,\ 0)\to x=4,\ y=0\\\\0=4(4)-4\\0=16-4\\0=12\qquad\bold{FALSE}](https://tex.z-dn.net/?f=y%3D4x-4%5C%5C%5C%5C%5Ctext%7BSubstitute%20the%20coordinates%20of%20each%20points%20to%20the%20equation%7D%5C%5C%5Ctext%7Band%20check%20the%20equality.%7D%5C%5C%5C%5C1.%5C%20%280%2C%5C%204%29%5Cto%20x%3D0%2C%5C%20y%3D4%5C%5C%5C%5C4%3D4%280%29-4%5C%5C4%3D0-4%5C%5C4%3D-4%5Cqquad%5Cbold%7BFALSE%7D%5C%5C%5C%5C2.%5C%20%280%2C%5C%20-4%29%5Cto%20x%3D0%2C%5C%20y%3D-4%5C%5C%5C%5C-4%3D4%280%29-4%5C%5C-4%3D0-4%5C%5C-4%3D-4%5Cqquad%5Cbold%7BTRUE%7D%5C%5C%5C%5C3.%5C%20%28-4%2C%5C%200%29%5Cto%20x%3D-4%2C%5C%20y%3D0%5C%5C%5C%5C0%3D4%28-4%29-4%5C%5C0%3D-16-4%5C%5C0%3D-20%5Cqquad%5Cbold%7BFALSE%7D%5C%5C%5C%5C4.%5C%20%284%2C%5C%200%29%5Cto%20x%3D4%2C%5C%20y%3D0%5C%5C%5C%5C0%3D4%284%29-4%5C%5C0%3D16-4%5C%5C0%3D12%5Cqquad%5Cbold%7BFALSE%7D)
Answer:
B
Step-by-step explanation:
#1.
[4x = -12y + 16 and x + 3y = 4]
One answer
#2.
Here, y = 4x + 3
y - 4x = 3
Multiply by 2,
2y - 8x = 6
Compare with second equation,
6 ≠ 3
In short, System of Equation does not have any solution. [ Option D ]
#3.
2y=6
3x-6y=18
Divide first equation by 2: y=3
Substitute y=3 into second equation: 3x-6(3)=18
Solve for x: 3x=36 x=12
Therefore there is only one solution: x=12 y=3
#4.
y - 7x = -14
7y - 49x = -2
Rewrite the first equation as "y =" so that it can be substituted into the second equation and solve for x.
y = 7x - 14
7(7x - 14) - 49x = -2
49x - 98 - 49x = -2
-98 = -2
Since the variables cancel and the equation is not true there is no solution.
The lines are parallel and will not intersect.