2500x0.80=2000 so i think it would be 2000 in 8 years
or if youre adding the 2000 to the already existing 2500 then it would be 4500.
Answer:
5 pigs
Step-by-step explanation:
A farmhouse shelters 16 animals, some are pigs, and some are ducks. Altogether there are 42 legs. How many pigs are there?
Let us represent:
Number of pigs = x
Number of ducks = y
Our system of equations is given as:
A farmhouse shelters 16 animals, some are pigs, and some are ducks.
x + y = 16...... Equation 1
x = 16 - y
Altogether there are 42 legs.
Ducks have 2 legs(feet) , pigs have 4 legs,
4x + 2y = 42..... Equation 2
We substitute
16 - y for x in Equation 2
Hence:
4(16 - y) + 2y = 42
64 - 4y + 2y = 42
Collect like terms
- 4y + 2y = 42 - 64
-2y =- 22
y = -22/-2
y = 11 ducks
Solving for x.
x = 16 - y
x = 16 - 11
x = 5 pigs
Therefore, we have 5 pigs
Answer:
A computer costs $225 and a printer $150.
Step-by-step explanation:
Let c be the cost of a computer and p the cost of a printer, then:
3c + p = 825
4c + 2p = 1200
Multiply the first equation by -2:
-6c - 2p = -1650
Add this to the second equation:
-2c = -450
c = 225.
Now substitute c = 225 in the first equation:
3*225 + p = 825
p = 825 - 675 = 150.
Hope it helps and pls mark as brainliest
Answer:
a) The 95% confidence interval to estimate the average fee for the population is between $11.65 and $12.79
b) $0.57
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
So the answer for b) is $0.57.
The lower end of the interval is the sample mean subtracted by M. So it is 12.22 - 0.57 = $11.65
The upper end of the interval is the sample mean added to M. So it is 12.22 + 0.57 = $12.79
The 95% confidence interval to estimate the average fee for the population is between $11.65 and $12.79
