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vladimir1956 [14]
3 years ago
10

Mr. Hammond is the volunteer coordinator for a company that puts on running races. Last year, the company organized 7 short race

s and 8 long races, which required a total of 804 volunteers. This year, the company organized 11 short races and 5 long races, which required 688 volunteers in total. How many volunteers does each type of race require?
Mathematics
1 answer:
worty [1.4K]3 years ago
4 0

Answer:

28 short race volunteers

76 long race volunteers

Step-by-step explanation:

Let :

Short races = a

Long races = b

LAST YEAR:

7a + 8b = 804 - - - - (1)

THIS YEAR:

11a + 5b = 688 - - - (2)

Multiply (1) by 5 and (2) by 8

35a + 40b = 4020

88a + 40b = 5504

Subtract

-53a = - 1484

a = 1484 / 53

a = 28

Put a = 28 in equation (1)

7(28) + 8b = 804

196 + 8b = 804

8b = 804 - 196

8b = 608

b = 76

28 short race volunteers

76 long race volunteers

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Let's call the two numbers x and y.

We know that x+y = 842 and that x-y = 314

Now that we have two equations, we can solve using substitution by solving for one variable in one of the equations, and plugging that in for the same variable in the other equation.

Lets solve for x in the second equation to get:

x = 314 + y

Now plug in 314+y for x in the first equation:

(314 + y) + y = 842

Combine like terms:

314 + 2y = 842

Now solve for y:

2y = 842-314

2y = 528

y = 264

Finally, plug 264 in for y to solve for x:

x + 264 = 842

x = 842-264

x = 578

The two numbers are 578 and 264.

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