Answer:
depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
Step-by-step explanation:
- First calculate the amount of depreciation/ton
- depreciation per ton = $125,000/208,000 = $0.600 /ton
- Hence depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
The best way to find your answer is to divide 193 by 400 to get .4825 and to make sure if it is the answer you take 400 and multiply .4825 and it will be 193 so .4825 = 48.25%
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Using a t-distribution calculator and finding the p-value, the correct option regarding the conclusion is given by:
a) the p-value is 0.02. We reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05.
<h3>What is the relation between the p-value and the conclusion?</h3>
It also involves the significance level, as follows.
- If the p-value is less than the significance level, we reject the null hypothesis
.
- If it is more, we do not reject.
In this problem, a t-distribution calculator for a right-tailed with <em>t = 2.15 and 25 - 1 = 24 df</em> is used to find a p-value of 0.02.
It is less than 0.05, hence option a is correct.
More can be learned about p-values at brainly.com/question/26454209
To work out the decrease, do original amount - new amount and then take that answer and divide it by the original amount, and then multiply by 100.
So you would do:
36.24 - 30.80 = 5.44
5.44 ÷ 36.24 × 100 = 15% to the nearest percent.