Given:
n = 50, sample size
, sample mean
s = 2.4 min, sample standard deviation.
The confidence interval is
At the 99% confidence level, t* (from the student's t-distribution) is
t* = 2.68
Therefore
t*(s/√n) = 2.68*(2.4/√50) = 0.9096
The confidence interval is
(23.6-0.9096, 23.6+0.9096) ≈ (22.69, 24.51)
Answer: (22.7, 24.5)
Answer:
(-5, 2)
Step-by-step explanation:
Three corners of a rectangular city block are located at (2,2), (2,-4) and (-5,-4) on a coordinate plane. What are the coordinates of the fourth Coordinate?
Solution:
A rectangle is a quadrilateral (has four sides and four angles) in which opposite sides are equal and parallel. Also, all the angles are at 90 degrees.
Since the city block is rectangular in shape, therefore the fourth coordinate would have the same y coordinate as the point (2, 2) and it would also have the same x coordinate as (-5, -4).
Hence the fourth coordinate is (-5, 2)
Answer:
150° and 210°
Step-by-step explanation:
1) according to the condition the required cosine is <0, it means the required angles are in the II-d and III-d quaters (see the attached picture no. 1);
2) it is known, that arccos(√3/2)=30°- the angle is between 0° and 90°, - but the requred angles are between 90° and 270° (see the picture no. 2), then
3) (angle)₁=180°-arccos(√3/2) and (angle)₂=180°+arccos(√3/2), then finally
(angle)₁=180°-30°=150°; (angle)₂=180°+30°=210°.
PS. note, the suggested way is not the only one.
Neato
um
requires some trial and error
erm
ah hah
what 2 numbers multiply to get 16 and add to get -8
-4 and -4
(x-4y)(x-4y)
(x-4y)²
