Answer:
They both have area 4
Step-by-step explanation:
Area of the square:
![base*height = 2 * 2 = 4](https://tex.z-dn.net/?f=base%2Aheight%20%3D%202%20%2A%202%20%3D%204)
Area of the triangle:
Using the left-side of the triangle as the base, and the height from the left-side to the bottom-right corner:
![\frac{1}{2}base*height](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dbase%2Aheight)
![\frac{1}{2}4\sqrt2*\sqrt2=4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D4%5Csqrt2%2A%5Csqrt2%3D4)
We know the length of the diagonal is
as we are using a centimetre grid, so we can create an isosceles triangle with side lengths 1 and our unknown length, we can then use Pythagorean Theorem to work out our unknown side length.
![a^2+b^2=c^2](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%5E2)
![1^2+1^2=c^2](https://tex.z-dn.net/?f=1%5E2%2B1%5E2%3Dc%5E2)
![2=c^2](https://tex.z-dn.net/?f=2%3Dc%5E2)
![\sqrt2=c](https://tex.z-dn.net/?f=%5Csqrt2%3Dc)
3x moved 3 units to the left, -5y moved 14 units to the right.
The probability of it being greater than one on a six sided die is 5/6 or 5:6
Answer:
Rational!
Step-by-step explanation:
The decimal is terminating so this is rational.