Question

Let f (x) = 10/x-4

Answer 1

Answer:

1.875

Step-by-step explanation:

The rate of change is the derivative of the function.

$f(x) = \frac{10}{x-4}\\\\f'(x)=10\times \frac {d}{dx}\frac{1}{x-4}\\\\f'(x)=\frac{-10}{(x-4)^{2}}\\\\f'(2) = \frac{-10}{(2-4)^{2}} =-2.5\\\\f'(8)= \frac{-10}{(8-4)^{2}} =-0.625$

So, the rate of change is

f'(8) -  f'(2) = - 0.625 + 2.5 = 1.875